On Fri, 2 Jun 2006, Aditya Mahajan wrote:
> Hi,
> I am trying to write a macro so that
>
> \SEQ X[1,2,3] expands to $X_1, X_2, X_3$
> \SEQ X[1-N] expands to $X_1, \dots, X_N$
> and
> \SEQ X expands to ${\bf X}$.
>
> So far I have
On Fri, 2 Jun 2006, Taco Hoekwater wrote:
> It is much easier to
On Fri, 2 Jun 2006, Taco Hoekwater wrote:
> Aditya Mahajan wrote:
>>>
>>> \def\dodoSEQ#1#2%
>>>{\ifdone ,\else \donetrue\fi#1_{#2}}
>>
>> Thanks Taco,
>>
>> Works like ... er ... magic. Where is \done set to true?
>
> Right above here, in \dodoSEQ.
Duh... I need to read TeX code more care
Aditya Mahajan wrote:
>>
>> \def\dodoSEQ#1#2%
>>{\ifdone ,\else \donetrue\fi#1_{#2}}
>
> Thanks Taco,
>
> Works like ... er ... magic. Where is \done set to true?
Right above here, in \dodoSEQ.
Taco
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On Fri, 2 Jun 2006, Taco Hoekwater wrote:
> Aditya Mahajan wrote:
>> There is an extra comma at the end. That is,
>>
>> \SEQ X[1,2,3] expands to $X_1,X_2,X_3,$
>> ^^^
>>
>> How can I treat the last element of a commalist differently?
>
> It is much easier to tr
Aditya Mahajan wrote:
> There is an extra comma at the end. That is,
>
> \SEQ X[1,2,3] expands to $X_1,X_2,X_3,$
> ^^^
>
> How can I treat the last element of a commalist differently?
It is much easier to treat the first element as special:
\def\doSEQ[#1]
Hi,
I am trying to write a macro so that
\SEQ X[1,2,3] expands to $X_1, X_2, X_3$
\SEQ X[1-N] expands to $X_1, \dots, X_N$
and
\SEQ X expands to ${\bf X}$.
So far I have
\def\SEQ#1%
{\dodoubleempty\doSEQ[#1]}
\def\doSEQ[#1][#2]%
{\ifsecondargument \mathematics{\processcommalist[#2]{\dodoSE
