On 30/10/2019 22:42, Elliot Hallmark wrote:
> I wouldn't be surprised at all if calling max in addition to argmax
> wasn't as fast or faster than indexing the array using argmax.
> Regardless, just use that then profile when you're done with the
> whole thing and see if there's any gains to be made
I wouldn't be surprised at all if calling max in addition to argmax wasn't
as fast or faster than indexing the array using argmax. Regardless, just
use that then profile when you're done with the whole thing and see if
there's any gains to be made. Very likely not here.
-elliot
On Wed, Oct 30, 20
On 30/10/2019 19:10, Neal Becker wrote:
> max(axis=1)?
Hi Neal,
I should have been more precise in stating the problem. Getting the
values in the array for which I'm looking at the maxima is only one step
in a more complex piece of code for which I need the indexes along the
second axis of the ar
max(axis=1)?
On Wed, Oct 30, 2019, 7:33 PM Daniele Nicolodi wrote:
> Hello,
>
> this is a very basic question, but I cannot find a satisfying answer.
> Assume a is a 2D array and that I get the index of the maximum value
> along the second dimension:
>
> i = a.argmax(axis=1)
>
> Is there a bette
Hello,
this is a very basic question, but I cannot find a satisfying answer.
Assume a is a 2D array and that I get the index of the maximum value
along the second dimension:
i = a.argmax(axis=1)
Is there a better way to get the value of the maximum array entries
along the second axis other than:
