On Fri, Aug 11, 2023, at 12:04, Ralf Gommers wrote:
> We've landed some major changes in `main` this week, so I thought it's a good
> idea to keep everyone in the loop.
This is a *significant* amount of work. Thank you, Ralf, for keeping track of
all the moving parts and for working with the res
Hey all,
We've landed some major changes in `main` this week, so I thought it's a
good idea to keep everyone in the loop.
First the good news: we now have full SIMD support in the Meson builds on
`main`! This was a huge amount of work by Sayed, so I'd like to say thank
you to him for doing all th
On Fri, 2023-08-11 at 13:43 -0400, Benjamin Root wrote:
> I'm really confused. Summing from zero should be what cumsum() does
> now.
>
What they mean is *including* the "implicit" 0 in the result. There
are some old NumPy issues on this, suggesting something like a new
kwarg like `include_initia
On 11 Aug 2023, at 7:52 pm, Robert Kern
mailto:robert.k...@gmail.com>> wrote:
>>> np.cumsum([[1, 2, 3], [4, 5, 6]])
array([ 1, 3, 6, 10, 15, 21])
```
which matches your example in the cumsum0() documentation. Did something change
in a recent release?
That's not what's in his example.
The exa
This has come up before, see https://github.com/numpy/numpy/issues/6044 for
the first time this came up; there were several subsequent discussions
linked there.
In the meantime, the data APIs consortium has been actively working on
adding a `cumulative_sum` function to the array API standard, see
After blinking and rubbing my eyes, I finally see what is meant by all of
this. I see now that the difference is that `cumsum0()` would return a
result that essentially have 0 be prepended to what would normally be the
result from `cumsum()`. From the description, I thought the "problem" was
that t
On Fri, Aug 11, 2023 at 1:47 PM Benjamin Root wrote:
> I'm really confused. Summing from zero should be what cumsum() does now.
>
> ```
> >>> np.__version__
> '1.22.4'
> >>> np.cumsum([[1, 2, 3], [4, 5, 6]])
> array([ 1, 3, 6, 10, 15, 21])
> ```
> which matches your example in the cumsum0() doc
I'm really confused. Summing from zero should be what cumsum() does now.
```
>>> np.__version__
'1.22.4'
>>> np.cumsum([[1, 2, 3], [4, 5, 6]])
array([ 1, 3, 6, 10, 15, 21])
```
which matches your example in the cumsum0() documentation. Did something
change in a recent release?
Ben Root
On Fri,
I'm very sensitive to the issues of adding to the already bloated numpy API,
but I would definitely find use in this function. I literally made this error
(thinking that the first element of cumsum should be 0) just a couple of days
ago! What are the plans for the "extended" NumPy API after 2.0?
`cumsum` computes the sum of the first k summands for every k from 1. Judging
by my experience, it is more often useful to compute the sum of the first k
summands for every k from 0, as `cumsum`'s behaviour leads to fencepost-like
problems.
https://en.wikipedia.org/wiki/Off-by-one_error#Fencepos
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