On Sat, Feb 25, 2023 at 8:17 PM Louis Petingi
wrote:
> Hi Robert
>
> Just a follow up. I was able (my student) to get the 1 vector from the 0
> eigenvector. Even though the normalized or this set of eigenvectors will
> work we could try the two sets. Not sure if multiplying the unit vectors by
>
Hi Robert
I read somewhere that we can use the unit vector times a scalar for the
Friedler eigenvector. Thus, the question is that for the first k-eigenvectors
do we multiply the corresponding unit vectors them by the same scalar? That
said my feeling is that when applying k-mean on the first k
On Sat, Feb 25, 2023 at 5:33 PM Louis Petingi
wrote:
> As you mentioned this is a generalization of the Fiedler eigenvector. When
> applying spectral clustering, and you want to find the two clusters
> then the Fiedler eigenvector tells you how to partition the vertices
> (bipartition) so the nor
