On Fri, Jun 3, 2022, at 23:54, Brinley Patterson wrote: > Hi, > > By using the exponential equation: > > exp(x) = (sum{k=0}{n} 1/ k! ) ^ x > > the speed and accuracy of calculating exponent greatly increases. Plus > it makes it easier to use with imaginary numbers. I have the python > function code if you are interested to learn more about this. This > equation can then be used to calculate sine and cos more efficiently > using the exponent form of them both.
Hi, From the equation you posted it sounds like your recommendation is to compute `e` from a truncated Taylor series, and then raise that number to the `x`th power. But we already know "the" double-precision value of `e`, a.k.a. `exp(1)`. So the recommended alternative would be more work than using double-precision `e` and then raising _that_ to the `x`th power. So this makes me think that I missed your point. Could you please try elaborating on your recommendation? AndrĂ¡s > > Kind regards, > > Brinley > MSc Machine Learning > BSc Mathematical Physics > _______________________________________________ > NumPy-Discussion mailing list -- numpy-discussion@python.org > To unsubscribe send an email to numpy-discussion-le...@python.org > https://mail.python.org/mailman3/lists/numpy-discussion.python.org/ > Member address: deak.and...@gmail.com _______________________________________________ NumPy-Discussion mailing list -- numpy-discussion@python.org To unsubscribe send an email to numpy-discussion-le...@python.org https://mail.python.org/mailman3/lists/numpy-discussion.python.org/ Member address: arch...@mail-archive.com