dear members,
I'm very sorry to bother you with a (hopefully) simple problem...
I need pyhton and the numerical package to run another program.
I installed Python, it works fine. But I can't install the numpy package. To
install the oder Numeric package was no problem, but I need the newer
It could be a version mismatch between two gcc (and the corresponding
libraries) versions: you surly have gcc at /usr/bin, but the fortran compiler
you use (g77) is as /usr/local/bin.
Nadav
-הודעה מקורית-
מאת: [EMAIL PROTECTED] בשם Christoph G?bl
נשלח: ו 24-אוקטובר-08 11:49
אל:
Hi,
I have to send this request second time since my first message contains the
attached data file which is too big and was blocked by the system. So this time
I will not attach the data file.
I have converted a matlab function to python using numpy. both matlab and
python run slow. I
Dear numpy users,
I need to pass a Numeric array to some oldie code from a numpy array. I
decided to go like this:
for i in range(BIGNUMER):
my_numpy_array=grabArray(i)
na=Numeric.array( my_numpy_array, Numeric.Float)
oldie_code(na)
The constructor line:
na=Numeric.array(
Jose Borreguero wrote:
Dear numpy users,
I need to pass a Numeric array to some oldie code from a numpy array.
I decided to go like this:
for i in range(BIGNUMER):
my_numpy_array=grabArray(i)
na=Numeric.array( my_numpy_array, Numeric.Float)
oldie_code(na)
The constructor
numpy 1.1.0 (from /usr/lib/python2.4/site-packages/numpy/version.py)
Numeric 24.2 (from
/usr/lib/python2.4/site-packages/Numeric/numeric_version.py)
I also tried with an intermediate list, but got the same result:
*mylist=list(my_numpy_array)
na=Numeric.array( mylist, Numeric.Float)*
I don't have
My bad. Using the intermediate list does *not* leak.
Still, the original problems stays. Can anyone run the following code in
their machine and see if they have leaks?
Maybe it only happens to me :(*
import numpy,Numeric
big=1000
na=numpy.array([0.0,])
for i in range(big):
Fri, 24 Oct 2008 14:39:59 -0400, Jose Borreguero wrote:
My bad. Using the intermediate list does *not* leak. Still, the original
problems stays. Can anyone run the following code in their machine and
see if they have leaks? Maybe it only happens to me :(*
import numpy,Numeric
big=1000
On Fri, Oct 24, 2008 at 7:52 PM, Pauli Virtanen [EMAIL PROTECTED] wrote:
Yep, leaks also here: (Numeric 24.2, numpy 1.2.0)
import sys, numpy, Numeric
na = numpy.array([0.0])
for i in xrange(100):
foo = Numeric.array(na, Numeric.Float)
print
Hi
I have 2 vectors A and B. For each value in A I want to find the location
in B of the same value. Both A and B have unique elements.
Of course I could something like
For each index of A:
v =A[index]
location = numpy.where(B == v)
But I have very large lists and it will take too
On Fri, Oct 24, 2008 at 3:48 PM, Mathew Yeates [EMAIL PROTECTED] wrote:
Hi
I have 2 vectors A and B. For each value in A I want to find the location
in B of the same value. Both A and B have unique elements.
Of course I could something like
For each index of A:
v =A[index]
h. I don't understand the result.
If
a=array([ 1, 2, 3, 7, 10]) and b=array([ 1, 2, 3, 8, 10])
I want to get the result [0,1,2,4] but[searchsorted(a,b) produces
[0,1,2,4,4] ?? and searchsorted(b,a) produces [0,1,2,3,4]
??
Mathew
On Fri, Oct 24, 2008 at 3:12 PM, Charles R Harris
On Fri, Oct 24, 2008 at 4:23 PM, Mathew Yeates [EMAIL PROTECTED] wrote:
h. I don't understand the result.
If
a=array([ 1, 2, 3, 7, 10]) and b=array([ 1, 2, 3, 8, 10])
I want to get the result [0,1,2,4] but[searchsorted(a,b) produces
[0,1,2,4,4] ?? and searchsorted(b,a) produces
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