On 2011-07-28 07:50, Johan Råde wrote:
How do I get the PyTypeObject* for a NumPy scalar type such as np.uint8?
(The reason I'm asking is the following:
I'm writing a C++ extension module. The Python interface to the module
has a function f that takes a NumPy scalar type as an argument, for
hey, i have an algorithm that computes two matrices like that:
A(i,k) = (x(i,k) + y(i,k))/norm
B(i,k) = (x(i,k) - y(i,k))/norm
it would be convenient to have the method like that:
A, B = mod.meth(C, prob=.95)
is ith possible to return two arrays?
best regards
Am Donnerstag, 28. Juli 2011, 17:42:38 schrieb Matthew Brett:
If I understand you correctly, the problem is that, for 1.5.1:
class Test(np.ndarray): pass
type(np.min(Test((1,
type 'numpy.float64'
and for 1.6.0 (and current trunk):
class Test(np.ndarray): pass
On Fri, Jul 29, 2011 at 9:52 AM, Yoshi Rokuko yo...@rokuko.net wrote:
hey, i have an algorithm that computes two matrices like that:
A(i,k) = (x(i,k) + y(i,k))/norm
B(i,k) = (x(i,k) - y(i,k))/norm
it would be convenient to have the method like that:
A, B = mod.meth(C, prob=.95)
is ith
Am Freitag, 29. Juli 2011, 11:31:24 schrieb Hans Meine:
Am Donnerstag, 28. Juli 2011, 17:42:38 schrieb Matthew Brett:
Was there a particular case you ran into where this was a problem?
[...]
Basically, the problem arose because our ndarray subclass does not support
zero-rank-instances fully.
+ Peter ---+
On Fri, Jul 29, 2011 at 9:52 AM, Yoshi Rokuko yo...@rokuko.net wrote:
hey, i have an algorithm that computes two matrices like that:
A(i,k) = (x(i,k) + y(i,k))/norm
B(i,k) = (x(i,k) - y(i,k))/norm
it would be
Fri, 29 Jul 2011 10:52:12 +0200, Yoshi Rokuko wrote:
[clip]
A, B = mod.meth(C, prob=.95)
is ith possible to return two arrays?
The way to do this in Python is to build a tuple with
Py_BuildValue(OO, A, B) and return that.
___
NumPy-Discussion
On Fri, Jul 29, 2011 at 4:12 AM, Hans Meine me...@informatik.uni-hamburg.de
wrote:
Am Freitag, 29. Juli 2011, 11:31:24 schrieb Hans Meine:
Am Donnerstag, 28. Juli 2011, 17:42:38 schrieb Matthew Brett:
Was there a particular case you ran into where this was a problem?
[...]
Basically,
On Thu, Jul 28, 2011 at 3:09 PM, Nathaniel Smith n...@pobox.com wrote:
I have a different question about this than the rest of the thread. I'm
confused at why there isn't a programmatic way to create a datetime dtype,
other than by going through this special string-based mini-language. I guess
Hi All,
I am fresh on this list and would be looking forward to as much help as I
can get. I am hoping to develop ino helping others too after a short while.
Kindly help me with this task.
I would appreciate if you can point me to an example or brief explanation.
I have a 4 by 4 matrix filled
As part of supporting the NA mask, I've rewritten boolean indexing. Here's a
timing comparison of my version versus a previous version:
In [2]: np.__version__
Out[2]: '1.4.1'
In [3]: a = np.zeros((1000,1000))
In [4]: mask = np.random.rand(1000,1000) 0.5
In [5]: timeit a[mask] = 1.5
10 loops,
I've merged a pull request from Alok Singhal which implements Robert Kern's
idea for this.
Thanks,
Mark
On Wed, Jul 27, 2011 at 12:50 PM, Matthew Brett matthew.br...@gmail.comwrote:
Hi,
I see that (current trunk):
In [9]: np.ones((1,), dtype=bool)
Out[9]: array([ True], dtype='bool')
-
On Fri, Jul 29, 2011 at 02:55:15PM +0100, DIPO ELEGBEDE wrote:
I have a 4 by 4 matrix filled with 0s, 1s and 2s.
I want to loop through the whole matrix to get the fields with 1s and 2s
only and then count how many ones and how many twos.
Try this:
m =
On Jul 29, 2011, at 4:07 PM, Mark Wiebe wrote:
As part of supporting the NA mask, I've rewritten boolean indexing. Here's a
timing comparison of my version versus a previous version:
In [2]: np.__version__
Out[2]: '1.4.1'
In [3]: a = np.zeros((1000,1000))
In [4]: mask =
Thanks Martins, that did the magic.
Thanks so much.
I'm on the tutorials now.
Regards.
On 29 Jul 2011 15:24, Martin Ling martin-nu...@earth.li wrote:
On Fri, Jul 29, 2011 at 02:55:15PM +0100, DIPO ELEGBEDE wrote:
I have a 4 by 4 matrix filled with 0s, 1s and 2s.
I want to loop through the
On Thu, Jul 28, 2011 at 09:48:29PM -0500, Robert Love wrote:
Quaternions have a handedness or a sign convention. The recently
departed Space Shuttle used a Left versor convention while most
things, including Space Station, use the right versor convention, in
their flight software. Made for
On Thu, Jul 28, 2011 at 9:58 AM, Hans Meine me...@informatik.uni-hamburg.de
wrote:
Hi again!
Am Donnerstag, 21. Juli 2011, 16:56:21 schrieb Hans Meine:
import numpy
class Test(numpy.ndarray):
pass
a1 = numpy.ndarray((1,))
a2 = Test((1,))
assert type(a1.min()) ==
On Fri, Jul 29, 2011 at 9:03 AM, Martin Ling martin-nu...@earth.li wrote:
On Thu, Jul 28, 2011 at 09:48:29PM -0500, Robert Love wrote:
Quaternions have a handedness or a sign convention. The recently
departed Space Shuttle used a Left versor convention while most
things, including Space
On 7/28/11 4:21 PM, Matthew Brett wrote:
Hi,
Do you know if doctests supports any sort of manual intervention, like
a plugin system?
Actually, I was going to ask you that question :)
But yes, there's the NumpyDoctest nose plugin, for example. Using it
does mean you have to customize nose
On Fri, Jul 29, 2011 at 10:07 AM, Mark Wiebe mwwi...@gmail.com wrote:
On Thu, Jul 28, 2011 at 9:58 AM, Hans Meine
me...@informatik.uni-hamburg.de wrote:
Hi again!
Am Donnerstag, 21. Juli 2011, 16:56:21 schrieb Hans Meine:
import numpy
class Test(numpy.ndarray):
pass
a1 =
On Fri, Jul 29, 2011 at 09:14:00AM -0600, Charles R Harris wrote:
Well, if the shuttle used a different definition then it was out there
somewhere. The history of quaternions is rather involved and mixed up with
vectors, so it may be the case that there were different conventions.
On Jul 28, 2011 8:43 AM, Matthew Brett matthew.br...@gmail.com wrote:
So, 1.6.0 is returning a zero-dimensional scalar of the given type,
and 1.5.1 returns a python scalar.
Zero dimensional scalars are designed to behave in a similar way to
python scalars, so the change should be all but
+-- Pauli Virtanen ---+
Fri, 29 Jul 2011 10:52:12 +0200, Yoshi Rokuko wrote:
[clip]
A, B = mod.meth(C, prob=.95)
is it possible to return two arrays?
The way to do this in Python is to build a tuple with
Py_BuildValue(OO, A, B) and return that.
that
On Fri, Jul 29, 2011 at 11:07 AM, Martin Ling martin-nu...@earth.li wrote:
On Fri, Jul 29, 2011 at 09:14:00AM -0600, Charles R Harris wrote:
Well, if the shuttle used a different definition then it was out there
somewhere. The history of quaternions is rather involved and mixed up
On Fri, Jul 29, 2011 at 2:52 PM, Charles R Harris charlesr.har...@gmail.com
wrote:
On Fri, Jul 29, 2011 at 11:07 AM, Martin Ling martin-nu...@earth.liwrote:
On Fri, Jul 29, 2011 at 09:14:00AM -0600, Charles R Harris wrote:
Well, if the shuttle used a different definition then it was
On Fri, Jul 29, 2011 at 1:57 PM, Benjamin Root ben.r...@ou.edu wrote:
On Fri, Jul 29, 2011 at 2:52 PM, Charles R Harris
charlesr.har...@gmail.com wrote:
On Fri, Jul 29, 2011 at 11:07 AM, Martin Ling martin-nu...@earth.liwrote:
On Fri, Jul 29, 2011 at 09:14:00AM -0600, Charles R Harris
On Fri, Jul 29, 2011 at 2:57 PM, Benjamin Root ben.r...@ou.edu wrote:
On Fri, Jul 29, 2011 at 2:52 PM, Charles R Harris
charlesr.har...@gmail.com wrote:
On Fri, Jul 29, 2011 at 11:07 AM, Martin Ling martin-nu...@earth.liwrote:
On Fri, Jul 29, 2011 at 09:14:00AM -0600, Charles R Harris
Dear numpy developers,
The current implementation of numpy.interp(x,xp,fp) comes down to: first
calculating all the slopes of the linear interpolant (these are len(xp)-1),
then use a binary search to find where x is in xp (running time
log(len(xp)). So we obtain a running time of
O( len(xp) +
Hi. That is really amazing.
I checked out that numexpr branch and saw some strange results when
evaluating expressions on a multi-core i7 processor.
Running the numexpr.test() yields a few 'F', which I suppose are failing
tests. I tried to let the tests finish but it takes more than 20 min, is
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