Excerpts from Xavier Barthelemy's message of mar. déc. 06 08:51:22 +0100 2011:
ok let me be more precise
I have an Z array which is the elevation
from this I extract a discrete array of Zero Crossing, and another discrete
array of Crests.
len(crest) is different than len(Xzeros). I have a
06.12.2011 08:49, Roger Binns kirjoitti:
Note that I am using regular Python lists (they were JSON at one point)
and the fft documentation is incomprehensible to someone who hasn't used
numpy before and only cares about fft (there are a lot of matches for
Google searches about fft and python
Yes I understood what you said. I know these tools, and I am using them.
I was just wandering if someone has a more one-liner-pythonic way to do it.
I don't think it's worth importing a new fortran module.
Thanks anyway :)
Xavier
2011/12/6 David Froger david.fro...@gmail.com
Excerpts from
Hi,
Is this intended?
[~/]
[1]: np.result_type(np.uint, np.int)
[1]: dtype('float64')
[~/]
[2]: np.version.version
[2]: '2.0.0.dev-aded70c'
Skipper
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Hi,
On Tue, Dec 6, 2011 at 4:45 AM, Skipper Seabold jsseab...@gmail.com wrote:
Hi,
Is this intended?
[~/]
[1]: np.result_type(np.uint, np.int)
[1]: dtype('float64')
I would guess so - if your system ints are 64 bit. int64 can't
contain the range for uint64, nor can uint64 contain all
On Tue, Dec 6, 2011 at 7:53 AM, Matthew Brett matthew.br...@gmail.com wrote:
Hi,
On Tue, Dec 6, 2011 at 4:45 AM, Skipper Seabold jsseab...@gmail.com wrote:
Hi,
Is this intended?
[~/]
[1]: np.result_type(np.uint, np.int)
[1]: dtype('float64')
I would guess so - if your system ints are
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On 06/12/11 01:58, Pauli Virtanen wrote:
I think this cannot be helped --- it does not make sense to explain
basic Numpy concepts in every docstring, especially `axis` and `shape`
are very common.
They don't need to be explained on the page, but
On Tue, Dec 6, 2011 at 2:51 AM, Xavier Barthelemy xab...@gmail.com wrote:
ok let me be more precise
I have an Z array which is the elevation
from this I extract a discrete array of Zero Crossing, and another
discrete array of Crests.
len(crest) is different than len(Xzeros). I have a
Dear all,
I can't wrap my head around this. Mathematically it's not hard, I just
don't know how to store and access it without many loops.
I have a function f(x,y).
I would like to calculate it at x = arange(20,101,20) and y = arange(2,30,2)
How do I store that in a multi-dimensional array
On 12/6/2011 8:32 AM, Roger Binns wrote:
I think this cannot be helped --- it does not make sense to explain
basic Numpy concepts in every docstring, especially `axis` and `shape`
are very common.
They don't need to be explained on the page, but instead link to a page
that does explain them.
On 12/6/2011 9:54 AM, K.-Michael Aye wrote:
I have a function f(x,y).
I would like to calculate it at x = arange(20,101,20) and y = arange(2,30,2)
How do I store that in a multi-dimensional array and preserve the grid
points where I did the calculation
In [5]: X, Y = np.meshgrid(range(3),
Travis Oliphant wrote:
My initial thoughts:
I don't have a horse in this race, but I do suggest people read Karl
Fogel's book before too much designing of governance structure:
http://producingoss.com/
(alas, it's not short, but it's a fairly easy read and you can get
convenient dead-tree or
On 6. des. 2011, at 17:32, Roger Binns wrote:
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On 06/12/11 01:58, Pauli Virtanen wrote:
I think this cannot be helped --- it does not make sense to explain
basic Numpy concepts in every docstring, especially `axis` and `shape`
are very
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Hash: SHA1
On 06/12/11 10:45, Paul Anton Letnes wrote:
As a side note: since the built-in search isn't really all that good,
would it be possible to put a customized google search box there
instead?
It is easy since Sphinx is being used. Copy searchbox.html
On Mon, Dec 5, 2011 at 8:43 PM, Ralf Gommers ralf.gomm...@googlemail.comwrote:
Hi all,
It's been a little over 6 months since the release of 1.6.0 and the NA
debate has quieted down, so I'd like to ask your opinion on the timing of
1.7.0. It looks to me like we have a healthy amount of bug
On Tue, Dec 6, 2011 at 4:11 PM, Ralf Gommers
ralf.gomm...@googlemail.com wrote:
On Mon, Dec 5, 2011 at 8:43 PM, Ralf Gommers ralf.gomm...@googlemail.com
wrote:
Hi all,
It's been a little over 6 months since the release of 1.6.0 and the NA
debate has quieted down, so I'd like to ask your
Hi,
How to make Numpy to match Matlab in term of performance ? I have tryied
with different options, using different MKL libraries and ICC versions,
still Numpy is below Matalb for certain basic tasks by ~2x. About 5 years
ago I was able to get about same speed, not anymore. Matlab suppose to use
On 06.12.2011, at 11:13PM, Wes McKinney wrote:
This isn't the place for this discussion but we should start talking
about building a *high performance* flat file loading solution with
good column type inference and sensible defaults, etc. It's clear that
loadtable is aiming for highest
I would like to produce an array with the maximum values out of many
(1s) of arrays.
I need to loop through many multidimentional arrays and if a value is
larger (in the same place as the previous array) then I would like that
value to replace it.
e.g.
a=[1,1,2,2
11,2,2
1,1,2,2]
b=[1,1,3,2
It may not be the most efficient way to do this, but you can do:
mask = b a
a[mask] = b[mask]
-=- Olivier
2011/12/6 questions anon questions.a...@gmail.com
I would like to produce an array with the maximum values out of many
(1s) of arrays.
I need to loop through many multidimentional
On Tue, Dec 6, 2011 at 7:55 PM, Olivier Delalleau sh...@keba.be wrote:
It may not be the most efficient way to do this, but you can do:
mask = b a
a[mask] = b[mask]
-=- Olivier
2011/12/6 questions anon questions.a...@gmail.com
I would like to produce an array with the maximum values out
On Mon, Dec 5, 2011 at 12:43 PM, Ralf Gommers
ralf.gomm...@googlemail.comwrote:
Hi all,
It's been a little over 6 months since the release of 1.6.0 and the NA
debate has quieted down, so I'd like to ask your opinion on the timing of
1.7.0. It looks to me like we have a healthy amount of bug
Hi Olivier,
No that does not seem to do anything
am I missing another step whereever b is greater than a replace b with a?
thanks
On Wed, Dec 7, 2011 at 11:55 AM, Olivier Delalleau sh...@keba.be wrote:
It may not be the most efficient way to do this, but you can do:
mask = b a
a[mask] =
thanks for responding Josef but that is not really what I am looking for, I
have a multidimensional array and if the next array has any values greater
than what is in my first array I want to replace them. The data are
contained in netcdf files.
I can achieve what I want if I combine all of my
Weird, it worked for me (with a and b two 1d numpy arrays). Anyway, Josef's
solution is probably much more efficient (especially if you can put all
your arrays into a single tensor).
-=- Olivier
2011/12/6 questions anon questions.a...@gmail.com
Hi Olivier,
No that does not seem to do anything
If you need to do them one after the other, numpy.maximum(a, b) will do it
(it won't work in-place on 'a' though, it'll make a new copy).
-=- Olivier
2011/12/6 questions anon questions.a...@gmail.com
thanks for responding Josef but that is not really what I am looking for,
I have a
I think you want
np.maximum(a, b, out=a)
- Nathaniel
On Dec 6, 2011 9:04 PM, questions anon questions.a...@gmail.com wrote:
thanks for responding Josef but that is not really what I am looking for,
I have a multidimensional array and if the next array has any values
greater than what is in
Thanks, I didn't know you could specify the out array :)
(to the OP: my initial suggestion, although probably not very efficient,
seems to work with 2D arrays too, so I have no idea why it didn't work for
you -- but Nathaniel's one seems to be the ideal one anyway).
-=- Olivier
2011/12/6
thanks for all of your help, that does look appropriate but I am not sure
how to loop it over thousands of files.
I need to keep the first array to compare with but replace any greater
values as I loop through each array comparing back to the same array. does
that make sense?
On Wed, Dec 7, 2011
The out=a keyword will ensure your first array will keep being updated.
So you can do something like:
a = my_list_of_arrays[0]
for b in my_list_of_arrays[1:]:
numpy.maximum(a, b, out=a)
-=- Olivier
2011/12/6 questions anon questions.a...@gmail.com
thanks for all of your help, that does look
On Tue, Dec 6, 2011 at 9:36 PM, Olivier Delalleau sh...@keba.be wrote:
The out=a keyword will ensure your first array will keep being updated. So
you can do something like:
a = my_list_of_arrays[0]
for b in my_list_of_arrays[1:]:
numpy.maximum(a, b, out=a)
I didn't think of the out
Is 'a' a regular numpy array or something fancier?
-=- Olivier
2011/12/6 questions anon questions.a...@gmail.com
thanks again my only problem though is that the out=a in the loop does not
seem to replace my a= outside the loop so my final a is whatever I started
with for a.
Not sure what I
I *think* it may work better if you replace the last 3 lines in your loop
by:
a=all_TSFC[0]
if len(all_TSFC) 1:
N.maximum(a, TSFC, out=a)
Not 100% sure that would work though, as I'm not entirely confident I
understand your code.
-=- Olivier
2011/12/6
On 07.12.2011, at 5:07AM, Olivier Delalleau wrote:
I *think* it may work better if you replace the last 3 lines in your loop by:
a=all_TSFC[0]
if len(all_TSFC) 1:
N.maximum(a, TSFC, out=a)
Not 100% sure that would work though, as I'm not entirely
On 07/12/2011, at 1:49 PM, questions anon wrote:
fillvalue=ncfile.variables['T_SFC']._FillValue
TSFC=MA.masked_values(TSFC, fillvalue)
You can probably also eliminate the above two lines from your code.
TSFC=ncfile.variables['T_SFC'][:]
If your NetCDF
sorry the 'all_TSFC' is for my other check of maximum using concatenate and
N.max, I know that works so I am comparing it to this method. The only
reason I need another method is for memory error issues.
I like the code I have written so far as it makes sense to me. I can't get
the extra examples
On 07.12.2011, at 5:54AM, questions anon wrote:
sorry the 'all_TSFC' is for my other check of maximum using concatenate and
N.max, I know that works so I am comparing it to this method. The only reason
I need another method is for memory error issues.
I like the code I have written so far
thanks for all your responses. I think I have FINALLY worked it out with
all of your help.
I just assigned one array from one ncfile to a at the beginning of my
code and then ran the loop and it worked!!
sorry for all the questions but I learn so much playing and getting ideas
from others.
Thanks
Hi Nathaniel,
The results of running memtest was a pass with no errors.
-Karl
Nathaniel Smith wrote:
(You should still run memtest. It's very easy - just install it with your
package manager, then reboot. Hold down the shift key while booting, and
you'll get a boot menu. Choose memtest,
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