On 5/22/12 9:08 PM, Massimo Di Pierro wrote:
> This problem is linear so probably Ram IO bound. I do not think I
> would benefit much for multiple cores. But I will give it a try. In
> the short term this is good enough for me.
Yeah, this what common sense seems to indicate, that RAM IO bound
pro
hi all,
maybe you're aware of numpypy - numpy port for pypy (pypy.org) - Python
language implementation with dynamic compilation.
Unfortunately, numpypy developmnent is very slow due to strict quality
standards and some other issues, so for my purposes I have provided some
missing numpypy funcs
That's very usefull! I hope these features get included upstream in the
next release of numpypy.
thanks,
Flávio
On Thu, May 24, 2012 at 8:32 AM, Dmitrey wrote:
> hi all,
> maybe you're aware of numpypy - numpy port for pypy (pypy.org) - Python
> language implementation with dynamic compilatio
On Thu, May 24, 2012 at 12:32 PM, Dmitrey wrote:
> hi all,
> maybe you're aware of numpypy - numpy port for pypy (pypy.org) - Python
> language implementation with dynamic compilation.
>
> Unfortunately, numpypy developmnent is very slow due to strict quality
> standards and some other issues, so
>
On your website you wrote:
>> From my (Dmitrey) point of view numpypy development is
>> very unfriendly for newcomers - PyPy developers say "provide
>> code, preferably in interpreter level instead of AppLevel,
>> provide whole test coverage for all possible corner cases,
>> provide hg diff
On Thu, May 24, 2012 at 2:07 PM, Dmitrey wrote:
>
> I had been subsribed IIRC for a couple of months
I don't follow the PyPy IRC so that would explain it. I don't know how
much they use that rather than their mailing list, but both seem a
better place to discuss their handling or external contrib
On 05/23/2012 05:31 PM, T J wrote:
> It seems that there are a number of ways to check if an array is a view.
> Do we have a preferred way in the API that is guaranteed to stay
> available? Or are all of the various methods "here to stay"?
We've settled on checking array.base, which I think was t
On Thu, May 24, 2012 at 10:56 AM, Jonathan T. Niehof wrote:
> On 05/23/2012 05:31 PM, T J wrote:
>
> > It seems that there are a number of ways to check if an array is a view.
> > Do we have a preferred way in the API that is guaranteed to stay
> > available? Or are all of the various methods "her
On Thu, May 24, 2012 at 3:56 PM, Jonathan T. Niehof wrote:
> On 05/23/2012 05:31 PM, T J wrote:
>
>> It seems that there are a number of ways to check if an array is a view.
>> Do we have a preferred way in the API that is guaranteed to stay
>> available? Or are all of the various methods "here to
On Thu, May 24, 2012 at 4:10 PM, Nathaniel Smith wrote:
> On Thu, May 24, 2012 at 3:56 PM, Jonathan T. Niehof wrote:
>> On 05/23/2012 05:31 PM, T J wrote:
>>
>>> It seems that there are a number of ways to check if an array is a view.
>>> Do we have a preferred way in the API that is guaranteed t
This is the stack overflow discussion mentioned.
http://stackoverflow.com/questions/9164269/can-you-tell-if-an-array-is-a-view-of-another
I basically implemented the answer from SO. I feel like the "is" gives you a
good handle on things since to be true they are actually the same location in
m
On Thu, May 24, 2012 at 6:07 PM, Larsen, Brian A wrote:
> This is the stack overflow discussion mentioned.
>
> http://stackoverflow.com/questions/9164269/can-you-tell-if-an-array-is-a-view-of-another
>
> I basically implemented the answer from SO. I feel like the "is" gives you
> a good handle on
On Thu, May 24, 2012 at 1:59 PM, Nathaniel Smith wrote:
> On Thu, May 24, 2012 at 6:07 PM, Larsen, Brian A wrote:
>> This is the stack overflow discussion mentioned.
>>
>> http://stackoverflow.com/questions/9164269/can-you-tell-if-an-array-is-a-view-of-another
>>
>> I basically implemented the an
thanks a lot. I updated the question on stackoverflow and opened a ticket
http://projects.scipy.org/numpy/ticket/2139
björn
Am Montag, 21. Mai 2012, 15:37:36 schrieb Travis Oliphant:
This is the right place to ask, it's just that it can take time to get an
answer because people who might k
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