Hi Stefan,
Thanks for the kindly reply...
Since both those objects have an __array_priority__ of 0.0, I guess it
just takes whichever class comes first.
In [15]: class A(np.ndarray):
: __array_priority__ = -1.0
I think, playing more...
For np.multiply, it does not seem possible
2008/8/28 Matthew Brett [EMAIL PROTECTED]:
np.multiply.outer, always returns an ndarray type, regardless of the
subtypes it is passed.
Sorry, I don't know what I was thinking. You are right!
Cheers
Stéfan
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Hi Travis and team,
I am just writing some docs for subclassing, and ran into some
behavior I didn't understand:
In [143]: class A(np.ndarray): pass
In [144]: arr = np.arange(5)
In [145]: obj = arr.copy().view(A)
In [146]: type(obj)
Out[146]: class '__main__.A'
In [147]:
Hey Matthew
2008/8/27 Matthew Brett [EMAIL PROTECTED]:
In [148]: type(np.multiply(arr, obj)) # this is what I expected
Out[148]: class '__main__.A'
In [149]: type(np.multiply.outer(arr, obj)) # this is not - I expected
class A again
Out[149]: type 'numpy.ndarray'
Since both those objects
