On 4/29/07, Kevin Jacobs <[EMAIL PROTECTED]> <[EMAIL PROTECTED]>
wrote:
On 4/29/07, Andrew Straw <[EMAIL PROTECTED]> wrote:
>
> No, the nth index of a Python sequence is a[n], where n starts from
> zero. Thus, if I want the nth dimension of array a, I want a.shape[n].
>
> I reverted the page to
On 4/29/07, Andrew Straw <[EMAIL PROTECTED]> wrote:
No, the nth index of a Python sequence is a[n], where n starts from
zero. Thus, if I want the nth dimension of array a, I want a.shape[n].
I reverted the page to its original form and added a couple explanatory
comments about zero vs one based
On 4/29/07, Andrew Straw <[EMAIL PROTECTED]> wrote:
> No, the nth index of a Python sequence is a[n], where n starts from
> zero. Thus, if I want the nth dimension of array a, I want a.shape[n].
>
> I reverted the page to its original form and added a couple explanatory
> comments about zero vs one
I think it's better to add "see remark!" inside the cells
because not all people read the text from 4th column
and this can lead to serious mistakes and lot of time elapsed for bug
hunting.
WBR, D.
Andrew Straw wrote:
> No, the nth index of a Python sequence is a[n], where n starts from
> zero. T
No, the nth index of a Python sequence is a[n], where n starts from
zero. Thus, if I want the nth dimension of array a, I want a.shape[n].
I reverted the page to its original form and added a couple explanatory
comments about zero vs one based indexing.
dmitrey wrote:
> now there is
> MATLAB
On 4/29/07, dmitrey <[EMAIL PROTECTED]> wrote:
> now there is
> MATLABNDArray Matrix
> size(a,n) a.shape[n] a.shape[n]
>
> but it should be
> size(a,n) a.shape[n-1] a.shape[n-1]
I made the change. But how should we change the comment?
now there is
MATLABNDArray Matrix
size(a,n) a.shape[n] a.shape[n]
but it should be
size(a,n) a.shape[n-1] a.shape[n-1]
WBR, D.
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