or:
a=array([1,2,3]).reshape((-1,1))
Darn, I guess there is more than one obvious way to do it!
-Chris
--
Christopher Barker, Ph.D.
Oceanographer
Emergency Response Division
NOAA/NOS/OR&R(206) 526-6959 voice
7600 Sand Point Way NE (206) 526-6329 fax
Seattle, WA 98115
On Sun, May 13, 2007 at 07:46:47AM -0400, Darren Dale wrote:
> On Sunday 13 May 2007 7:36:39 am dmitrey wrote:
> > i.e. for example from flat array [1, 2, 3] obtain
> > array([[ 1.],
> >[ 2.],
> >[ 3.]])
>
> a=array([1,2,3])
> a.shape=(len(a),1)
Or just
a.shape = (-1,1)
Cheers
S
On Sunday 13 May 2007 7:36:39 am dmitrey wrote:
> i.e. for example from flat array [1, 2, 3] obtain
> array([[ 1.],
>[ 2.],
>[ 3.]])
a=array([1,2,3])
a.shape=(len(a),1)
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On Sun, May 13, 2007 at 02:36:39PM +0300, dmitrey wrote:
> i.e. for example from flat array [1, 2, 3] obtain
> array([[ 1.],
>[ 2.],
>[ 3.]])
>
> I have numpy v 1.0.1
> Thx, D.
Use newaxis:
In [1]: a = array([1., 2., 3.])
In [2]: a
Out[2]: array([ 1., 2., 3.])
In [3]: a[:,newax
i.e. for example from flat array [1, 2, 3] obtain
array([[ 1.],
[ 2.],
[ 3.]])
I have numpy v 1.0.1
Thx, D.
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