Re: SQL help needed

2003-09-20 Thread Stephane Faroult
Tim Gorman wrote: Great idea, Mark! By the way, does anyone remember the yes command in UNIX? Same concept. I think it was invented to answer ³yes² to any program which mindlessly prompt for ³yes/no² responses in situations where only ³yes² makes sense. Case in point: ³fsck². As in:

Re: SQL help needed

2003-09-20 Thread Jared Still
y y y y y .. On Fri, 2003-09-19 at 22:09, Tim Gorman wrote: Great idea, Mark! By the way, does anyone remember the yes command in UNIX? Same concept. I think it was invented to answer yes to any program which mindlessly prompt for yes/no responses in situations where only yes makes sense.

Re: SQL help needed

2003-09-20 Thread Binley Lim
y y y y Continue to repair or build a new filesystem- Do you want to build a new filesystem (y/n)? y Oops ;-) .. On Fri, 2003-09-19 at 22:09, Tim Gorman wrote: Great idea, Mark! By the way, does anyone remember the yes command in UNIX? Same concept. I think it was invented to

Re: SQL help needed

2003-09-19 Thread Tim Gorman
Great idea, Mark! By the way, does anyone remember the yes command in UNIX? Same concept. I think it was invented to answer ³yes² to any program which mindlessly prompt for ³yes/no² responses in situations where only ³yes² makes sense. Case in point: ³fsck². As in: ³Do you want to repair this

Re: Re: SQL help needed

2003-09-18 Thread Tanel Poder
You raise an interesting idea in my mind... How useful would it be for us if Oracle created an INFINITE_DUAL table - One where you could select as many rows as you wished. I guess it might be dangerous but it would at least be very efficient if Oracle coded it as a special table. Then you

Re: SQL help needed

2003-09-17 Thread GovindanK
You would require something like this: http://asktom.oracle.com/pls/ask/f?p=4950:8:F4950_P8_DISPLAYID:504432994857 HTH GovindanK Hello Listers, I need some SQL help. Not sure if this is possible in plain SQL or not, but here it is: I have a table with two columns: EMPNBR LINENBR

RE: Re: SQL help needed

2003-09-17 Thread Stephane Faroult
I was thinking along the same lines minus the outer query which is totally unnecessary, but it is the beginning of my day here :-). SF - --- Original Message --- - From: Wolfgang Breitling [EMAIL PROTECTED] To: Multiple recipients of list ORACLE-L [EMAIL PROTECTED] Sent: Tue,

RE: Re: SQL help needed

2003-09-17 Thread Stephane Faroult
- --- Original Message --- - From: Mark Richard [EMAIL PROTECTED] To: Multiple recipients of list ORACLE-L [EMAIL PROTECTED] Sent: Tue, 16 Sep 2003 19:59:41 I guess I should have added some criteria like: 1) user_objects must have enough rows in it to cover the range (if not

CORRECTION RE: RE: Re: SQL help needed

2003-09-17 Thread Stephane Faroult
create viex xdual as select rownum ID from sys.col$; Cannot have a column named rownum ... Going to be a difficult day. And we are only half-week. Regards, Stephane Faroult Oriole -- Please see the official ORACLE-L FAQ: http://www.orafaq.net -- Author: Stephane Faroult INET: [EMAIL

Re: CORRECTION RE: RE: Re: SQL help needed

2003-09-17 Thread Guido Konsolke
Hi Stephane, I commiserate with you 8-) Regards, Guido [EMAIL PROTECTED] 17.09.2003 10.44 Uhr create viex xdual as select rownum ID from sys.col$; Cannot have a column named rownum ... Going to be a difficult day. And we are only half-week. Regards, Stephane Faroult Oriole -- Please

Re: Re: SQL help needed

2003-09-17 Thread Tanel Poder
Hi! This one is a very interesting consideration. The use of 'pivot' tables, as in this case, without being something you meet daily is fairly frequent (completing series like here is one usage, otherwise I commonly use them to generate test data). It should be some standard feature, a kind of

Re: SQL help needed

2003-09-17 Thread Kirtikumar Deshpande
Hello All, Thanks for your wonderful ideas. I just forwarded those to my dear Developer (my wife, that is :) After posting my question to the list last night, I was told that the query will be run against an Informix database :) Typical Developers !!! ;) Cheers! - Kirti ---

RE: SQL help needed

2003-09-17 Thread Jacques Kilchoer
I know you said that this was Informix, but I'll post the article below anyway for the benefit of other listers. Oracle Technology Network Oracle Magazine September/October 2002 Turning On Pivot Tables By Jonathan Gennick http://otn.oracle.com/oramag/oracle/02-sep/o52sql.html Describes a method

Re: SQL help needed

2003-09-17 Thread bulbultyagi
Hey there kirti , good to have you back. - Original Message - To: Multiple recipients of list ORACLE-L [EMAIL PROTECTED] Sent: Wednesday, September 17, 2003 19:09 Hello All, Thanks for your wonderful ideas. I just forwarded those to my dear Developer (my wife, that is :) After

RE: Re: SQL help needed

2003-09-17 Thread Mark Richard
] [EMAIL PROTECTED]cc: orp.com Subject: RE: Re: SQL help needed

Re: SQL help needed

2003-09-16 Thread Mark Richard
Easy select rownum+minlinenbr-1 from user_objects where rownum = maxlinenbr-minlinenbr minus select linenbr from table Replace the words with bind variables or whatever is appropriate for your application. Oh, and be sure to test it for accuracy - I'm typing without testing and could be

Re: SQL help needed

2003-09-16 Thread Mladen Gogala
There is no way you can do it without some procedural programming. PL/SQL is easy and, knowing you and your great knowledge , I'm not going to offer that kind of advice. SQL was modelled on the set theory, which essentially means that you are selecting subset, based on relatively static criteria

Re: SQL help needed

2003-09-16 Thread Mark Richard
[EMAIL PROTECTED] ban.com.au cc: Sent by: Subject: Re: SQL help needed

Re: SQL help needed

2003-09-16 Thread Wolfgang Breitling
How about select linenbr from (select rownum+min as linenbr from dba_objects where rownum (max-min) minus select linenbr from kirti where linenbr min and linenbr max) / pollux.stats.scott select * from kirti; EMPNBRLINENBR -- -- 100 1 200

RE: SQL HELP.....

2003-08-29 Thread Cabansay, Yoyong
Naveen, J J J You are rightthe table is structured that way. I want to find at which point in the carton numbers from 1 to 600 does have Item C. The final output would be like: Item C: Carton# Item qty weight 1-48 C 46 20 281-310 C 20 14 And so on. Thanks in advance

RE: SQL HELP.....

2003-08-28 Thread Stephane Faroult
De-aggregating aggregated values is an endeavour comparable to putting the toothpaste back into the tube. You can't. If you have the detail somewhere, read about MINUS and INTERSECT, or possibly NOT EXISTS. - --- Original Message --- - From: Cabansay, Yoyong [EMAIL PROTECTED]

RE: SQL HELP.....

2003-08-28 Thread Naveen Nahata
"Open the cartons and see!" ;-) By the way can you reframe your question? Do you mean that you table stores data as follows: item carton_no qty weight - --- -- A1 410 A 2 4 10 B 1 5 12 B 3 5 12 C 1 35 and so on? RegardsNaveen -Original Message-From:

RE: SQL HELP!!!

2003-08-27 Thread Jamadagni, Rajendra
Try something like ... select id, col_1, col_2,sum(web_c),sum(other_c) from (select id, to_char(received_date,'-MM') col_1,yr||seq_no||ck col_2, case when seq_no 4000 then 1 else 0 end web_c, case when seq_no= 4000 then 1 else 0 end other_c from t where received_date between

RE: SQL HELP - SOLVED!!!

2003-08-27 Thread Viktor
Thanks to ALL for your help on this! As always your advice is greatly appreciated! Viktor"Jamadagni, Rajendra" [EMAIL PROTECTED] wrote: Try something like ... select id, col_1, col_2,sum(web_c),sum(other_c) from (select id, to_char(received_date,'-MM') col_1,yr||seq_no||ck col_2, case

Re: SQL HELP!!!

2003-08-26 Thread Jared . Still
I'm not sure I entirely understand the result you are trying to achieve. Perhaps this will help select received_date, msno, sum(count_web), hardcopy from ( select id , to_char(received_date, '-mm') received_date, id||yr||seq_no||ck MSNO CASE WHEN seq_no 4000 then

Re: SQL HELP!!!

2003-08-26 Thread Viktor
Jared, Thanks for your fast reply! Sorry if I didn't explain myself clear enough. Unfortunately count_web is not a column, id||yr||seq_no||ck is a combination of 4 columns that make up a primary key. if seq_no 4000,in aid||yr||seq_no||ck row, it's a"web row", if not then it's not. what I would

Re: SQL HELP!!!

2003-08-26 Thread Viktor
Dave, Thanks much! I appreciate your help. One other thing I might have forgotten is there a way to calculate non_web_count - to - total% and web_count - to total % so in this way: output would be like: ID YEARNON WEB % WEB %NON-WEB AC 2003-01 47 9867.6 32.4AC 2003-02 26 112AC 2003-03 57

Re: SQL HELP!!!

2003-08-26 Thread Dave Hau
select id, received_date, count(count_non_web) non_web_count, count(count_web) web_count, (count(count_non_web) / count(*) * 100) non_web_count_percent, (count(count_web) / count(*) * 100) web_count_percent from (select id, to_char(received_date, '-mm') received_date, (case when seq_no = 4000

Re: SQL HELP!!!

2003-08-26 Thread Viktor
PROTECTED] 08/26/2003 01:29 PM To:[EMAIL PROTECTED], [EMAIL PROTECTED] cc: Subject: Re: SQL HELP!!!Jared, Thanks for your fast reply! Sorry if I didn't explain myself clear enough. Unfortunately count_web is not a column, id||yr||seq_no||ck is a combination of

Re: SQL HELP!!!

2003-08-26 Thread Dave Hau
select id, received_date, count(count_non_web) non_web_count, count(count_web) web_count from (select id, to_char(received_date, '-mm') received_date, (case when seq_no = 4000 then 1 else null end) count_non_web, (case_when seq_no 4000 then 1 else null end) count_web from t where

Re: SQL HELP!!!

2003-08-26 Thread Jared . Still
Viktor, By using an inline view, count_web does indeed become a column. Did you try the query? Jared Viktor [EMAIL PROTECTED] 08/26/2003 01:29 PM To:[EMAIL PROTECTED], [EMAIL PROTECTED] cc: Subject:Re: SQL HELP!!! Jared, Thanks for your fast reply

RE: SQL help

2002-09-13 Thread Rick_Cale
by: Subject: RE: SQL help [EMAIL PROTECTED] om

RE: SQL help

2002-09-12 Thread Jamadagni, Rajendra
Title: RE: SQL help Not tested but select sysdate, 'test1','test2' from dual where exists ( your union clause) union your_union_clause Raj __ Rajendra Jamadagni MIS, ESPN Inc. Rajendra dot Jamadagni at ESPN dot com Any opinion

RE: SQL help

2002-09-12 Thread Fink, Dan
Title: RE: SQL help Rick, Is this in SQL*Plus? If so, use the COLUMN command to populate the column headings with the information you want. You can populate a variable with SYSDATE and use that in the column heading. Dan -Original Message-From: Jamadagni, Rajendra [mailto

RE: SQL help

2002-09-12 Thread Larry Elkins
If you don't want to apply criteria to the first part to see if data from the second part is returned, you can avoid it by using an analytic function. Ok, the examples below might look a little complex, but basically you have your UNION ALL in the inner most in-line view. In the in-line view

Re: SQL Help Urgent!!!!!!!!!

2002-05-13 Thread sree
Hello sultan You can create a view for the cc table and use with the bb table to display the output . create view cc_view as select id, sum(amount) amt from cc group by id select a.id,a.amount ,b.amount from bb a,cc_view b where a.id=b.id; Hope this solution work's for u. I will also

RE: SQL Help Urgent!!!!!!!!!

2002-05-12 Thread Vikas Khanna
Select a.id,a.amount,ccinlineview.bamt from bb a,(Select id,sum(b.amount) bamt from cc b group by id) ccinlineview where a.id = ccinlineview.id ID AMOUNT BAMT -- -- -- 1 1000 1000 1 row selected. -Original Message-From: sultan [mailto:[EMAIL

Re: SQL Help Urgent!!!!!!!!!

2002-05-12 Thread Stephane Faroult
sultan wrote: Hi gurus I have two tables like this SQL select * from bb; ID AMOUNT DT -- -- -- 1 1000 10-MAY-02 SQL select * from cc; ID AMOUNT --

RE: SQL help

2002-04-29 Thread Pardee, Roy E
This should get you a list of the combos of ID, Company Country that are repeated in the table: warning--air SQL! SELECT ID, Company, Country, COUNT(*) NumRecs FROMmy_table GROUP BY ID, Company, Country HAVING COUNT(*) 1 /warning--air SQL! Or if you need all the records that belong to

Re: SQL help

2002-04-29 Thread Bunyamin K. Karadeniz
Here is your answer, SELECT ID,COMPANY,COUNTRY FROM table_name a WHERE rowid (SELECT min(rowid) FROM table_name b WHERE b.ID = a.ID and a.COMPANY= b.COMPANY and a.COUNTRY=b.COUNTRY) ; Replace Select witth DELETE if you want to delete duplicates. Bunyamin K.

Re: SQL help

2002-04-29 Thread Stephane Faroult
k k wrote: Hello all, I need some SQL help .. I have a table with containing duplicate records but because they have differents status they really are duplicate .. i need to find these .. here is an example of what the table contains : IDCompany Country Status 5521 ABC

Re: SQL help

2002-04-29 Thread Ora NT DBA
HI K, You didn't say whether you have (or want) a unique constraint on these fields, but if you did (or do) you may consider the use of the exceptions table to identify which rows violate these constraints. An example below: SQL create table junk (id varchar2(4), company varchar2(3), 2

RE: sql help

2001-07-23 Thread Kevin Lange
select distinct segment_type, owner, segment_name, tablespace_name from dba_segments This will get them all in one simple query. -Original Message- Sent: Saturday, July 21, 2001 10:45 AM To: Multiple recipients of list ORACLE-L hi dba's how to find out a users all objects+the

RE: sql help

2001-07-22 Thread GL2Z/ INF DBA BENLATRECHE
Try this simple script set pagesize 66 linesize 132 verify off select tablespace_name Tablespace ,segment_type Object_type ,segment_name Object from user_extents order by tablespace_name,segment_type; -Message d'origine- De : kommareddy sreenivasa [mailto:[EMAIL PROTECTED]] Envoyé :

RE: sql help

2001-07-22 Thread Anand
Hi, Try this query :- SELECT * FROM ALL_OBJECTS WHERE OBJECT_NAME IN (SELECT SEGMENT_NAME FROM DBA_SEGMENTS); Regards, Anand. -Original Message- sreenivasa Sent: Saturday, July 21, 2001 9:15 PM To: Multiple recipients of list ORACLE-L hi dba's how to find out a users all

Re: sql help --urgent

2001-07-21 Thread Rangachari Sundar
Hi, Select a, decode(sign(a), -1, 0, a-1) from Table Name For summing up : sum(decode(sign(a), -1, 0, a-1)) Hope this helps Bye Sundar Ravindra Basavaraja wrote: I have a table with a number column(Col A).I want to display A-1.There could be some negative values in this A-1 column.But

Re: sql help

2001-07-21 Thread Jon Walthour
Srinivas: Try this: break on TYPE SELECT 'TABLE' AS TYPE , table_name AS object_name FROM sys.dba_tables WHERE owner = 'SCOTT' UNION SELECT 'INDEX' , index_name FROM sys.dba_indexes WHERE owner = 'SCOTT' UNION SELECT 'CLUSTER' , cluster_name FROM

Re: sql help --urgent

2001-07-20 Thread Ron Thomas
decode(sign(a), -1, 0, a) Ron Thomas Hypercom, Inc [EMAIL PROTECTED] I'm too sexy for my code. - Awk Sed Fred ravindra@sent

RE: sql help --urgent

2001-07-20 Thread Michael E. Cupp, Jr.
select sum(column) where column 0 or try a decode -Original Message- Basavaraja Sent: Friday, July 20, 2001 3:41 PM To: Multiple recipients of list ORACLE-L I have a table with a number column(Col A).I want to display A-1.There could be some negative values in this A-1 column.But I

RE: SQL HELP

2001-03-13 Thread Abdul Aleem
Use the function SUBSTR( TO_CHAR ( date_column, 'DAY' ),3) = 'FRI' in your where clause HTH! Aleem -Original Message- Sent: Wednesday, March 14, 2001 6:11 AM To: Multiple recipients of list ORACLE-L Subject:SQL HELP Hello, Now I know this must have been discussed here