: Saturday, August 24, 2013 7:58 PM
To: pwhiteho
Cc: Andy Bauer; paraview@paraview.org
Subject: Re: [Paraview] Stream Tracer in eigenvector field
Paul,
Sorry to have given such an off target answer! Your idea about checking the dot
product as you progress makes sense. That's how VTK's a hyper
*From:* Burlen Loring [blor...@lbl.gov]
*Sent:* Friday, August 23, 2013 4:31 PM
*To:* Andy Bauer; pwhiteho
*Cc:* paraview@paraview.org
*Subject:* Re: [Paraview] Stream Tracer in eigenvector field
Eigenvectors are unique up to a constantso if you took any eigenvector
and multiplied it by -1 it's
*From:* Burlen Loring [blor...@lbl.gov]
*Sent:* Friday, August 23, 2013 4:31 PM
*To:* Andy Bauer; pwhiteho
*Cc:* paraview@paraview.org
*Subject:* Re: [Paraview] Stream Tracer in eigenvector field
Eigenvectors are unique up
The term eigenvector, used to describe the principal directions of a tensor,
is a bit of a misnomer since it's not a vector as interpreted by the Stream
Tracer filter - it's more accurately bi-directional like tension/compression
and could be termed eigenaxis/eigenaxes. When interpreted as a
Hi Paul,
Apologies as my math is a bit rusty but isn't the sign of the eigenvector
related to the sign of its corresponding eigenvalue? In that case if you
make sure that all of the eigenvalues are positive then all of their
corresponding eigenvectors should be aligned properly. If that's the
Eigenvectors are unique up to a constantso if you took any eigenvector
and multiplied it by -1 it's still an eigenvector. You could see it in
the definition,
M x=\lambda x
eigenvector x appears in both sides of the eqn.
I had a similar problem with tensor glyphs in ParaView. In that case I
Oh boy, the math does slip away too fast :)
On Fri, Aug 23, 2013 at 4:31 PM, Burlen Loring blor...@lbl.gov wrote:
Eigenvectors are unique up to a constant so if you took any eigenvector
and multiplied it by -1 it's still an eigenvector. You could see it in the
definition,
M x=\lambda x
: Friday, August 23, 2013 4:31 PM
To: Andy Bauer; pwhiteho
Cc: paraview@paraview.org
Subject: Re: [Paraview] Stream Tracer in eigenvector field
Eigenvectors are unique up to a constant so if you took any eigenvector and
multiplied it by -1 it's still an eigenvector. You could see
