Guess I should search before I post. Just found Win32::DirSize. It is
MUCH faster than my previous code below and gives exactly what I need.
$Dir = "C:\\Windows";
print "\n\nGetting size of $Dir";
my $Result = dir_size($Dir, my $DirInfo);
if ($Result == DS_RESULT_OK) {
print "\tF
Guess I should search before I post. Just found Win32::DirSize. It is
MUCH faster than my previous code below and gives exactly what I need.
$Dir = "C:\\Windows";
print "\n\nGetting size of $Dir";
my $Result = dir_size($Dir, my $DirInfo);
if ($Result == DS_RESULT_OK) {
print "\tFi
I know how to get actual file size of a directory tree with Perl but can
anyone offer assistance in getting actual disk space required or what
windows calls "Size on Disk" of a directory tree.
Below is what I have to find actual data size of a tree but it does not
take into account wasted disk spa
> The following code has the benefit of using NT credentials of the
> currently logged in user. But, the currently logged in user needs to
> have access in Exchange. :)
>
> No passwords in clear text to glean from your scripts That's
> usually a good thing. :)
>
> $OLECon =
> Win32::OLE->G
