- Original Message -
From:
RCTay
To: [EMAIL PROTECTED]
Sent: Sunday, November 24, 2002 8:06
AM
Subject: Can arrays be used as
scalars?
my( @dir,
$free);@dir =3D `dir`;$free =3D $dir[$#dir];
This code was
written by a friend of mine. "@dir" wa
On 24/11/2002 08:06:35 RCTay wrote:
my( @dir, $free);
@dir =3D `dir`;
$free =3D $dir[$#dir];
This code was written by a friend of mine. @dir was declared as
a array, but
in the second line it is used as a scalar. How is that possible? There
are no
warnings given by the interpreter. Can you
please do not send me anymore email, thanks!
[EMAIL PROTECTED] wrote:
On 24/11/2002 08:06:35 RCTay wrote:my( @dir, $free);@dir =3D `dir`;$free =3D $dir[$#dir];This code was written by a friend of mine. "@dir" was declared asaarray, butin the second line it is used as a scalar. How is thatpossible?
