The result is the same andrew !
did u tried that snippet ?
i'm just running it , and noticed no changes .
could it be perl versions ?
i'm in perl 5.0.8 


Saber.


----- Original Message ----- 
From: <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Wednesday, June 25, 2003 11:20 AM
Subject: RE: Timout using eval


You just have to re-order things a bit I think, and remove the local:

 $SIG{ALRM}= sub {die "TIMEOUT_PASSED\n"};

 eval {
        alarm (3);
        printf " get character \n" ;
        $data = <> ;

  }; # eval  the eval block should take less  3 secs otherwise , timeout function is 
fired

  alarm (0);

  if ($@ =~ /TIMEOUT_PASSED/) {
                # treat timeout
                printf " TIMEOUT  : no data to read \n" ;
 }

-----Original Message-----
From: saber zrelli [mailto:[EMAIL PROTECTED]
Sent: 25 June 2003 09:32
To: [EMAIL PROTECTED];
[EMAIL PROTECTED]
Subject: Timout using eval


Hi ,
I'm trying to timeout an event , i'm searching for an implementation to perform that ,
i tried the eval die technique , but the result is not what i need  , this is a sample 
code :

-------------------------------
 my$data;

 eval {
        local $SIG{ALRM}= sub {die "TIMEOUT_PASSED\n"};
        alarm (3);
        printf " get character \n" ;
        $data = <> ;
        alarm (0);

  }; # eval  the eval block should take less  3 secs otherwise , timeout function is 
fired

  if ($@ =~ /TIMEOUT_PASSED/) {
                # treat timeout
                printf " TIMEOUT  : no data to read \n" ;
 }
 
-------------------------------

the above code , did not wait 3 secs for the user input , it waits forever !

Could someone help please.

Thks.



-----------------------------------
Saber ZRELLI
STMicroelectronics
Aplication Engineer Tunis VQT Team.
Office                   126
Personal Phone   +216  22552432




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