[perl #123168] [BUG] Statement-modifying if falsely detected as p5-idiomatic /i after assigning form of regex substitution in Rakudo

2014-11-10 Thread Carl Mäsak
# New Ticket Created by "Carl Mäsak" # Please include the string: [perl #123168] # in the subject line of all future correspondence about this issue. # https://rt.perl.org/Ticket/Display.html?id=123168 > hmmm, I've seen that before somewhere: ===SORRY!=== Error while compiling lib/Cache/Mem

[perl #111572] [BUG] Unicode problem with 2012.0 on Mac OSX 10.7.3

2014-11-10 Thread Christian Bartolomaeus via RT
With the latest parrot the tests in S19-command-line/dash-e.t pass on Mac OS X. I unfudged the tests with commit https://github.com/perl6/roast/commit/5d89b2877e and I'm closing this ticket now.

Re: Date truncated-to method argument?

2014-11-10 Thread Carl Mäsak
Moritz (>): > iirc there was a spec change. > > Let's check... > > $ ~/p6/specs (master)$ git log -p -S truncated > commit 9d8bc5fe62dd38805d791c0351c85185d351290e > Author: Carl Masak > Date: Thu Jan 24 18:27:55 2013 +0100 > > [S32/Temporal] spec DateTime.delta and Date.delta > > Clarif

Re: Date truncated-to method argument?

2014-11-10 Thread Moritz Lenz
Hi, On 11/10/2014 01:39 PM, Steve Mynott wrote: http://doc.perl6.org/type/Date says my $c = Date.new('2012-12-24'); say $c.truncated-to(:year); # 2012-01-01 but this doesn't work and what's implemented appears to be "year" rather than :year $ perl6 my $c = Date.new('2012-12-24'); 2012-1

Date truncated-to method argument?

2014-11-10 Thread Steve Mynott
http://doc.perl6.org/type/Date says my $c = Date.new('2012-12-24'); say $c.truncated-to(:year); # 2012-01-01 but this doesn't work and what's implemented appears to be "year" rather than :year $ perl6 > my $c = Date.new('2012-12-24'); 2012-12-24 > say $c.truncated-to("year") 2012-01-01 Whic