Sorry, I sent my answer just for you.
So, the problem is you didn't call the same var you had declared.
my $foo = * **2;
Then you call
foo(2).say
Missing the $
Try:
$foo(2).say
or
say $foo(2)
About the
my @a = * **2;
Your suggestion works
@a[0](2)
or
@a[0].(2)
But I would
>The * * * call generates a WhateverCode block. This is expecting 2 arguments.
-> $x { $x * $x } is taking one argument.
> The best documentation would probably be : https://docs.raku.org/type/Whatever
so, from:
Multiple * in one expression generate closures with as many arguments:
my $c = * +
Hi Timo,
Thanks for the answer:
> the liskov substitution principle
I didn't knew about this principle. I'm now going down the rabbit hole.
Is this always the case for all the derived classes in Raku?
Best regards,
David Santiago
Timo Paulssen escreveu no dia terça, 11/02/2020 à(s) 13:32:
>
>
The * * * call generates a WhateverCode block. This is expecting 2
arguments.
-> $x { $x * $x } is taking one argument.
The best documentation would probably be :
https://docs.raku.org/type/Whatever
Hope that helps.
(For giggles earlier I made this dumb example of functional programming)
my
I have a few less related questions
>> those are 3 ways to write the same sub:
sub foo ($x) { $x * $x }
my = -> $x { $x * $x }
my = * * *;
> A Note on Marc's comment:
my = * * *
is not the same as:
my = -> $x { $x * $x }
it is the same as:
my = -> $x, $y { $x * $y }
Okay, "* *
The problem is that you are using ~ with an uninitialized Buf/Blob
my Buf $read;
$read ~ Buf.new;
# Use of uninitialized value element of type Buf in string context.
Note that it is not complaining about it being a Buf. It is complaining
about it being uninitialized.
If you
On 11/02/2020 14:14, David Santiago wrote:
> Awesome explanation! Thank you!
>
> BTW,
>> my Blob $read = Buf.new;
> Is it creating either a Blob or a Buf?
>
> Regards,
> David Santiago
Hi David,
"my Blob $read" will define the variable $read to 1) only accept things
that typecheck against
Awesome explanation! Thank you!
BTW,
> my Blob $read = Buf.new;
Is it creating either a Blob or a Buf?
Regards,
David Santiago
--
Sent from my Android device with K-9 Mail. Please excuse my brevity.
On 11/02/2020 10:56, David Santiago wrote:
> Hi!
>
> Can someone explain me why this doesn't work:
>
> my Blob $read;
> $read ~= $socket.read(1024);
>
> Dies with error:
>
> X::Buf::AsStr: Cannot use a Buf as a string, but you called the Stringy
> method on it
>
> This also doesn't work:
>
> my
On 2020-02-11 01:03, ToddAndMargo via perl6-users wrote:
On 2020-02-11 00:44, Shlomi Fish wrote:
Hi Todd,
On Mon, 10 Feb 2020 19:25:50 -0800
ToddAndMargo via perl6-users wrote:
Hi All,
I have been getting a strange eMail on this group.
How do I contact the moderator to check and see
if it
A 11 de fevereiro de 2020 12:03:19 CET, Simon Proctor
escreveu:
>Ok I 100% don't know after trying this out :
>
>my Buf $a = Buf.new(1,2,3);
>my Blob $b = Blob.new(4,5,6);
>$a ~= $b;
>say $a
>
>And it worked fine so... I dunno.
>
>
>On Tue, 11 Feb 2020 at 11:00, Simon Proctor wrote:
>
>> I
Ok I 100% don't know after trying this out :
my Buf $a = Buf.new(1,2,3);
my Blob $b = Blob.new(4,5,6);
$a ~= $b;
say $a
And it worked fine so... I dunno.
On Tue, 11 Feb 2020 at 11:00, Simon Proctor wrote:
> I think the problem is IO::Socket.read() returns a Blob not a Buf.
>
> ~ has a Buf,
I think the problem is IO::Socket.read() returns a Blob not a Buf.
~ has a Buf, Buf variant : https://docs.raku.org/language/operators#infix_~
But not a Blob one. Buf does Blob but not vice versa.
I think you need to transform the output from .read into a Buf if you want
to use the ~= how you
~ works fine for concatenating Bufs; For example:
my $a = Buf.new(1,2,3);
my $b = $a ~ Buf.new(4,5,6)
will assign correctly to $b.
I can't work out what the problem is here, despite trying various
combinations. Perhaps socket isn't really returning a Blob?
Kevin.
On Tue, 11 Feb 2020 at 21:01,
Awesome, thanks!
That is exactly what I was looking for.
On Tue, 11 Feb 2020 at 10:23, Kevin Pye wrote:
> The "workaround" is well documented:
> https://docs.raku.org/language/create-cli#%*SUB-MAIN-OPTS
>
> It's just a matter of setting named-anywhere option in the %*SUB-MAIN-OPTS
> hash,
You are using ~, which stringifies. Bufs are not strings: you need to
decode them to concatenate it to a string. If what you want is to
concatenate the buffer, probably ,= will work (not sure about this, would
have to check), or any other operator that works on Positionals.
JJ
El mar., 11 feb.
A 11 de fevereiro de 2020 10:47:34 CET, David Santiago
escreveu:
>A 11 de fevereiro de 2020 09:46:06 CET, David Santiago
>escreveu:
>>
>>Hi!
>>
>>Can someone explain me why this doesn't work:
>>
>>my Blob $read;
>>$read ~= $socket.read(1024);
>>
>>Dies with error:
>>
>>X::Buf::AsStr: Cannot
The "workaround" is well documented:
https://docs.raku.org/language/create-cli#%*SUB-MAIN-OPTS
It's just a matter of setting named-anywhere option in the %*SUB-MAIN-OPTS
hash, which you will also need to create. There's an example in that doc
page.
Kevin.
On Tue, 11 Feb 2020 at 20:07, WFB
If you can store a subroutine in a variable then you can pass said
subroutine to another one as an argument.
This leads us into the joys of functional programming.
And you may have used it already and not even realised.
The .map and .grep methods (and .reduce and bunch of others) all expect a
Interesting stuff.
I would like to take the change and ask one question:
One thing, I had to get used to is the MAIN handling of parameters.
On the command line it is important to write then named parameter in front
of the positional ones:
MAIN('compile', :$verbose, :$test-only)
needs to write:
Hi Todd,
On Mon, 10 Feb 2020 19:25:50 -0800
ToddAndMargo via perl6-users wrote:
> Hi All,
>
> I have been getting a strange eMail on this group.
> How do I contact the moderator to check and see
> if it is a scam?
>
I think you should send an email to perl6-users-ow...@perl.org .
> Many
On 2020-02-11 00:44, Shlomi Fish wrote:
Hi Todd,
On Mon, 10 Feb 2020 19:25:50 -0800
ToddAndMargo via perl6-users wrote:
Hi All,
I have been getting a strange eMail on this group.
How do I contact the moderator to check and see
if it is a scam?
I think you should send an email to
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