ce dot to lay it out a bit more clearly. I don't
promise anything (I'm not a GraphViz expert by any stretch of the
definition), but it might be fun to try.
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Dakkar -
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und to the 2-ary signature
would leave the $a parameter without a value, and so undef (I'm assuming
that pointy sub positional parameters are implicitly optional, otherwise
that statement would be a run-time error). I'm pretty sure I don't know
what 'each' does...
6) It's wr
urnal might help you:
http://use.perl.org/~BooK/journal/25445
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Dakkar -
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6FE2 40EA 9883 7519 3F88
key id = 0x75193F88
signature.asc
Description: OpenPGP di
oo(Str $a) {return 3}
print $foo_A_H.('a');
should that print 3? Or coerce 'a' into ['a'] and print 1?
What about (thinking aloud):
my $foo_static=&foo;
my $foo_dynamic:=&foo;
where the first one has "snapshot" semanti
way to
express the "long name", and use that to get the ref. Is there any
proposed syntax for this? (I ask about syntax because the semantic seems
pretty clear...)
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Dakkar -
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6FE2
rint foo(1),foo('a');
should have the same effect? Printing 2 twice? I don't expect MMD on
non-multi subs.
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Dakkar -
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ch: it's quite possible that by adding 'defined'
in several places I broke something else. People familiar with the
code will undoubtedly correct my patch.
--
Dakkar -
Index: String.pm
===
RCS file: /cvs/public/par
On 20021007203856, Johan Vromans wrote:
> Here it prints "Yes r" and "Yes s" for perl = 5.6.0, 5.6.1, 5.8.0.
Yes, that's precisely the point... the current perl6 doesn't.
(oh, BTW, in the second line perl5 "promotes" the rhs string to a
regexp,
t;1" =~ /1/;
it does print "Yes r". I also tried:
$r= "0"=~/0/;
$s= "0"=~"0";
print '|',$r,"|\n";
print '|',$s,"|\n";
(the variable assignment is to (try to) avoid list context)
and it prints:
||
|
