Hi, there was some benchmarking and discussion about perl5 slowness in ... http://groups.google.at/group/perl.perl5.porters/browse_thread/thread/4ad7f6edacc97e1b/75af8abf89420f8c?hl=de& ... and of course there were some remarks re parrot.
I'm not subscribed to p5p, so feel free to forward the message. Here are the numbers[1] for that mentioned benchmark[2]: $ time perl mandel.pl >/dev/null && time ./parrot -j mandel.pir >/dev/null && time ./mandel >/dev/null real 0m3.314s user 0m3.300s sys 0m0.004s real 0m0.084s user 0m0.084s sys 0m0.000s real 0m0.029s user 0m0.024s sys 0m0.000s leo [1] on AMD [EMAIL PROTECTED], optimized parrot build of r27216 (-m32 --optimize) [2] perl and C code from http://www.timestretch.com/FractalBenchmark.html#4d9e0f15fc1b42420cf3f778c3cccad7 perl 5.8.8, C 4.1.0 (C compiled w/ -O3), optimized parrot build of r27216 (-m32 --optimize) parrot code is here: $ cat mandel.pir .const int BAILOUT = 16 .const int MAX_ITERATIONS = 1000 .sub mandelbrot .param num x .param num y .local num cr, ci, zr, zi .local int i cr = y - 0.5 ci = x zi = 0.0 zr = 0.0 i = 0 loop: inc i .local num temp, zr2, zi2 temp = zr * zi zr2 = zr * zr zi2 = zi * zi zr = zr2 - zi2 zr += cr zi = temp + temp zi += ci $N0 = zi2 + zr2 if $N0 > BAILOUT goto ret if i > MAX_ITERATIONS goto ret0 goto loop ret: .return (i) ret0: .return (0) .end .sub main :main .local num start, end start = time .local int x, y y = -39 loopy: if y >= 39 goto endy print "\n" x = -39 loopx: if x >= 39 goto endx .local int i $N0 = x / 40 $N1 = y / 40 i = mandelbrot($N0, $N1) if i == 0 goto pstar print ' ' goto pdone pstar: print '*' pdone: inc x goto loopx endx: inc y goto loopy endy: end = time $N2 = end - start $P0 = new 'ResizablePMCArray' push $P0, $N2 $S0 = sprintf "\nParrot Elapsed %0.2f\n", $P0 print $S0 .end