Leopold Toetsch [EMAIL PROTECTED] writes:
Piers Cawley [EMAIL PROTECTED] wrote:
Leopold Toetsch [EMAIL PROTECTED] writes:
Just use a Key PMC for $P2.
So, just for fun I added the following test to t/pmc/perlhash.t:
new P10, .PerlHash
new P1, .PerlString
set P1, Bar
new
--- Piers Cawley [EMAIL PROTECTED] wrote:
new P10, .PerlHash
new P1, .PerlString
set P1, Bar
new P2, .Key
set P2, P1
Oops! should be assign!
This is one of the reasons I think code like
$P0 = new PerlString
$P0 = foo
should be illegal. If people were forced to
Leopold Toetsch [EMAIL PROTECTED] writes:
Togos [EMAIL PROTECTED] wrote:
Should aggregate PMCs (like PerlHash) be able to take
PMCs as keys? I mean so that:
$P0 = $P1[$P2]
Just use a Key PMC for $P2.
$P2 = new Key
$P2 = key_string
...
So, just for fun I added the following
Piers Cawley [EMAIL PROTECTED] wrote:
Leopold Toetsch [EMAIL PROTECTED] writes:
Just use a Key PMC for $P2.
So, just for fun I added the following test to t/pmc/perlhash.t:
new P10, .PerlHash
new P1, .PerlString
set P1, Bar
new P2, .Key
set P2, P1
^^^
Cset Px,
Togos [EMAIL PROTECTED] wrote:
Should aggregate PMCs (like PerlHash) be able to take
PMCs as keys? I mean so that:
$P0 = $P1[$P2]
Just use a Key PMC for $P2.
$P2 = new Key
$P2 = key_string
...
leo
Le Thu, May 20, 2004 at 12:03:52PM -0700, le valeureux mongueur TOGoS a dit:
Should aggregate PMCs (like PerlHash) be able to take
PMCs as keys? I mean so that:
$P0 = $P1[$P2]
where $P1 is a PerlHash, would work. The way it works
now is that it complains that you can't use a PMC as a
Should aggregate PMCs (like PerlHash) be able to take
PMCs as keys? I mean so that:
$P0 = $P1[$P2]
where $P1 is a PerlHash, would work. The way it works
now is that it complains that you can't use a PMC as a
key. So my compiler has to spit out about 20 lines of
code for every sub-element
