On Tue, 12 Sep 2000 19:01:35 -0400, Mark-Jason Dominus wrote:
I don't know what you mean, but you're mistaken, because it means to
interpolate @foo as in a double-quoted string.
Which is precisely the meaning he wants for it, with $" set to '|'.
"Which is precisely the meaning he wants
On Wed 13 Sep, Bart Lateur wrote:
On Tue, 12 Sep 2000 19:01:35 -0400, Mark-Jason Dominus wrote:
I don't know what you mean, but you're mistaken, because it means to
interpolate @foo as in a double-quoted string.
Which is precisely the meaning he wants for it, with $" set to '|'.
I
On Tue, 12 Sep 2000 19:01:35 -0400, Mark-Jason Dominus wrote:
I don't know what you mean, but you're mistaken, because it means to
interpolate @foo as in a double-quoted string.
Which is precisely the meaning he wants for it, with $" set to '|'.
I wonder if we're not trying too hard. What if,
(The \ is necessary here because (?@foo) already has a meaning under
Perl 5, and I think your proposal must address this.)
(?@foo) has no meaning I checked the code
I don't know what you mean, but you're mistaken, because it means to
interpolate @foo as in a double-quoted string.
On Mon 11 Sep, Mark-Jason Dominus wrote:
(?@foo) is sort of equivalent to (??{join('|',@foo)}), ie it expands into
a list of alternatives. One could possible use just @foo, for this.
It just occurs to me that this is already possible. I've written a
module, 'atq', such that if you
This and other RFCs are available on the web at
http://dev.perl.org/rfc/
=head1 TITLE
Additions to regexs
=head1 VERSION
Maintainer: Richard Proctor [EMAIL PROTECTED]
Date: 27 Aug 2000
Mailing List: [EMAIL PROTECTED]
Version: 1
Number: 166
=head1
