Nicholas Clark wrote:
So I assume, that the returned PerlUndef should be put into the
aggregate, if there was none before access.
I believe yes, it must, for consistency.
Is there an op to copy the value out of an aggregate, without changing
the aggregate? The (shallow copy) value assignment, nee
Having read the whole thread a few times, I think I understand the
question.
On Fri, Aug 22, 2003 at 10:16:33AM +0200, Leopold Toetsch wrote:
> Benjamin Goldberg <[EMAIL PROTECTED]> wrote:
> >> (PMCs have reference semantics[1])
>
> I should have started with [1]:
>
> new P1, .PerlHash
> # n
On Friday, August 22, 2003, at 02:52 , Leopold Toetsch wrote:
Gordon Henriksen wrote:
(PMCs have reference semantics[1])
Isn't that the job of Perl's \ operator?
Did you read on to [1] too?
I read
[1]
new P1, .PerlHash
new P3, .PerlString
set P3, "yyy\n"
set P1["a"], P3
set P0, P1["a"]
Gordon Henriksen wrote:
(PMCs have reference semantics[1])
Isn't that the job of Perl's \ operator?
Did you read on to [1] too?
leo
Benjamin Goldberg <[EMAIL PROTECTED]> wrote:
>> (PMCs have reference semantics[1])
I should have started with [1]:
new P1, .PerlHash
# new P3, .PerlString
# set P3, "yyy\n"
# set P1["a"], P3
set P0, P1["a"]
print P0
set P0, "xxx\n"
set P2, P1["a"]
print P2
end
When the hash e
On Thursday, August 21, 2003, at 11:50 , Leopold Toetsch wrote:
IMHO is
$a = \$h{"a"};
print $$a;
$$a = "xxx\n";
$a = $h{"a"};
print $a;
the same as:
new P1, .PerlHash
set P0, P1["a"]
print P0
set P0, "xxx\n"
set P2, P1["a"]
print P2
end
(PMCs have reference semantics[1])
Leopold Toetsch wrote:
>
> IMHO is
>
>$a = \$h{"a"};
>print $$a;
>$$a = "xxx\n";
>$a = $h{"a"};
>print $a;
>
> the same as:
>
>new P1, .PerlHash
>set P0, P1["a"]
>print P0
>set P0, "xxx\n"
>set P2, P1["a"]
>print P2
>end
>
> (PMCs have referenc
IMHO is
$a = \$h{"a"};
print $$a;
$$a = "xxx\n";
$a = $h{"a"};
print $a;
the same as:
new P1, .PerlHash
set P0, P1["a"]
print P0
set P0, "xxx\n"
set P2, P1["a"]
print P2
end
(PMCs have reference semantics[1])
Shouldn't that print "xxx" as perl5 does? I.e. store the returne
