At 11:39 PM 12/20/00 +, Nicholas Clark wrote:
>On Wed, Dec 20, 2000 at 03:36:48PM -0800, Peter Scott wrote:
> > Should this second paragraph still be true for Perl 6? I have at times
> > wanted to do something of the form
> >
> > perl -lwe '$x = "x"; $y = "y"; $y =~ ($x eq "x" ? s/y/z/ : s/y/
On Wed, Dec 20, 2000 at 03:36:48PM -0800, Peter Scott wrote:
> Should this second paragraph still be true for Perl 6? I have at times
> wanted to do something of the form
>
> perl -lwe '$x = "x"; $y = "y"; $y =~ ($x eq "x" ? s/y/z/ : s/y/a/); print $y'
>
> but I have not wanted to make the rig
perlop:
>Binary ``=~'' binds a scalar expression to a pattern match. [...] The
>right argument is a search pattern, substitution, or transliteration. [...]
>
>If the right argument is an expression rather than a search pattern,
>substitution, or
>transliteration, it is interpreted as a search p
