At 12:04 AM -0700 9/18/02, Brent Dax wrote:
The Apocalypse on operators says that if one of the operands of a
hyperoperator is a scalar, then that scalar is (nominally) treated as an
array of copies of that scalar. In other words:
my $foo=1;
my @bar=(2, 3, 4);
my @baz=$foo
Steve Fink wrote:
What should this do:
my $x = the letter x;
print yes if $x =~ /the { $x .= ! } .* !/;
Does this print yes?
If it's allowed at all, I think the match should succeed.
print yes if helo =~ /hel { .pos-- } lo/;
This definitely has to work. But remember the call
On Wed, 18 Sep 2002, Damian Conway wrote:
Would it be correct for this to print 0? Would it be correct for this
to print 2?
my $n = 0;
aargh =~ /a* { $n++ } aargh/;
print $n;
Yes. ;-)
Wouldn't that print 2 if $n is lexical and 0 if it's localized? Or are
lexicals localized
On Wed, 2002-09-18 at 11:42, Piers Cawley wrote:
The Perl 6 Summary for the Week Ending 20020915
Happy birthday to me!
Indeed!
And thank you so much for this. You have a way of taking a tangled mess
of discussion that's even confusing the participants and making it easy
to digest (no pun
The Perl 6 Summary for the Week Ending 20020915
Happy birthday to me!
Happy birthday to me!
Happy birthday dear me!
Happy birthday to me!
And, with a single breech of copyright, Piers was free. The production
of this summary was delayed by my turning 35 on the 15th
On Wed, 18 Sep 2002, Josh Jore wrote:
On Wed, 18 Sep 2002, Damian Conway wrote:
Would it be correct for this to print 0? Would it be correct for this
to print 2?
my $n = 0;
aargh =~ /a* { $n++ } aargh/;
print $n;
Yes. ;-)
Wouldn't that print 2 if $n is lexical
Aaron Sherman [EMAIL PROTECTED] writes:
On Wed, 2002-09-18 at 11:42, Piers Cawley wrote:
The Perl 6 Summary for the Week Ending 20020915
Happy birthday to me!
Indeed!
And thank you so much for this. You have a way of taking a tangled mess
of discussion that's even confusing the