HaloO,
Autrijus Tang wrote:
1) I would move the ::name to the Pad level. The idea is
that ::name is some less specific supertype of the
Fantastique Four ($@%) if more than one of them exists
on the container level.
Please annotate this idea with the code. You mean:
my $a = 3;
HaloO,
Autrijus Tang wrote:
The first one is about the compilation cycle:
http://pugscode.org/images/simple-compilation.png
Question: where is the namespace in the picture?
I would expect it to be build in parallel to the
syntax tree between parser and compiler. From there
it might be
On Tue, Aug 09, 2005 at 02:06:58PM +0200, TSa wrote:
The first one is about the compilation cycle:
http://pugscode.org/images/simple-compilation.png
Question: where is the namespace in the picture?
I would expect it to be build in parallel to the
syntax tree between parser and
Stevan,
Up until today, I thought I had a good idea of how your metamodel
works, but now I'm confused. My main sticking point is that a class
Foo seems to have three different aspects:
Foo
class(Foo)
meta(Foo)
For each of these, could you please try to explain:
1) Roughly what its
Guten Tag Herr Sandlaß,
On Aug 9, 2005, at 4:48 AM, TSa (Thomas Sandlaß) wrote:
HaloO,
Stevan Little wrote:
Here is a 10,000 ft view of the metamodel prototype I sketched out
the other day
(http://svn.openfoundry.org/pugs/perl5/Perl6-MetaModel/docs/
10_000_ft_view.pod). It should shed a
HaloO,
Stuart Cook wrote:
So far, this is what I have picked up; some/most of it is probably wrong:
At least your confusion matches nicely with mine :)
~ Foo ~
Is a type that variables etc. can be declared to have
Is not an object
= I'm really not sure about this...
Bare Foo is a
HaloO Stevan,
you wrote:
Guten Tag Herr Sandlaß,
you know that a formal German greeting in a collequial
environment can be interpreted as unfriendly? I don't
do that but just wanted to state the fact.
The next level where a 1:n relation exists is below meta(Foo) to pure
meta.
Not
On Tue, Aug 09, 2005 at 06:36:28PM +0200, TSa wrote:
But Smalltalk is a typeless language that dispatches along the lines
of the (meta)class/(meta)object links. I propose to call this kind
of thing slot dispatch and reserve single and multi method dispatch for
the type based approach. Don't
Stuart,
On Aug 9, 2005, at 9:25 AM, Stuart Cook wrote:
Stevan,
Up until today, I thought I had a good idea of how your metamodel
works, but now I'm confused. My main sticking point is that a class
Foo seems to have three different aspects:
Foo
class(Foo)
meta(Foo)
For each of these, could
On Aug 9, 2005, at 12:36 PM, TSa wrote:
HaloO Stevan,
you wrote:
Guten Tag Herr Sandlaß,
you know that a formal German greeting in a collequial
environment can be interpreted as unfriendly? I don't
do that but just wanted to state the fact.
My apologies, no unfriendliness intended :)
The
On Aug 9, 2005, at 10:52 AM, TSa wrote:
~ Foo ~
Is a type that variables etc. can be declared to have
Is not an object
= I'm really not sure about this...
Bare Foo is a namespace lookup.
Yes, TSa is right. Everything below this is Type-stuff and I will leave
that to him (up until the
Howdy,
I wanted to make sure this question had a chance to get addressed, so I
am seperating it from the other thread which has digressed into the
depths of the metamodel (much to my delight too).
So..., as described in the other thread, the following statements are
true about the
On Tue, Aug 09, 2005 at 05:08:43PM -0400, Stevan Little wrote:
: Howdy,
:
: I wanted to make sure this question had a chance to get addressed, so I
: am seperating it from the other thread which has digressed into the
: depths of the metamodel (much to my delight too).
:
: So..., as described
More MOP related questions :)
In the p5 MetaModel, you can do the following:
$obj-meta-add_method('foo' =
Perl6::Method-create_instance_method(sub { ... }));
$obj-meta-add_method('foo' = Perl6::Method-create_class_method(sub
{ ... }));
$obj-meta-add_method('foo' =
On Tue, Aug 09, 2005 at 03:54:23PM -0400, Stevan Little wrote:
: Stuart,
:
: On Aug 9, 2005, at 9:25 AM, Stuart Cook wrote:
: Stevan,
:
: Up until today, I thought I had a good idea of how your metamodel
: works, but now I'm confused. My main sticking point is that a class
: Foo seems to have
Larry,
On Aug 9, 2005, at 6:18 PM, Larry Wall wrote:
: Personally I am not a fan of the 'is_a' name, I just did it one day,
: and it sort of stuck.
Well, hey, I'm not a fan of the isa name, so I guess we're even.
fair enough :)
: But I do think we need to find a way to
: differentiate
Larry,
On Aug 9, 2005, at 7:19 PM, Larry Wall wrote:
: So far, this is what I have picked up; some/most of it is probably
: wrong:
:
: ~ Foo ~
: Is a type that variables etc. can be declared to have
:
: That is one way to look at it I suppose. The reality is that there
will
: be no actual
17 matches
Mail list logo
