On Sat, May 26, 2012 at 6:34 PM, Nicholas Clark n...@ccl4.org wrote:
On Fri, May 25, 2012 at 08:44:30AM -0500, B. Estrade wrote:
Realistically, that's not going to happen. The internals of the Perl 5
interpreter are not flexible enough to implement a lot of the features
that
Perl 6 has
Congratulations!
On Thu, Jul 29, 2010 at 8:23 PM, Patrick R. Michaud pmich...@pobox.com wrote:
On behalf of the Rakudo and Perl 6 development teams, I'm happy to
announce the July 2010 release of Rakudo Star, a useful and usable
distribution of Perl 6. The tarball for the July 2010 release is
Is Int a proper type? I hope I can use basic operation within Date and hours
in perl6 like:
Date -1/24 + 1/24/60 + Date
On Fri, Apr 9, 2010 at 10:00 PM, Moritz Lenz mor...@faui2k3.org wrote:
Am 09.04.2010 15:33, schrieb Dave Rolsky:
On Thu, 8 Apr 2010, Carl Mäsak wrote:
I do
On Fri, Jul 10, 2009 at 12:29 AM, yary not@gmail.com wrote:
On Wed, Jul 8, 2009 at 8:45 PM, Xiao Yafeng xyf.x...@gmail.com wrote:
Any thoughts?
First let's fix the whitespace in your post so it's easier to read-
My question is: could I write below code in perl6:
# 2 loops like
My question is: could I write below code in perl6:
my @a = 1 2 3 4; my @b[2]; for @a -
@b {;} # 2 loops like for @a - $b[0],$b[1]{;}
my @a = 1 2 3 4; my @b; for @a - @b
{;} # 1 loop
, Timothy S. Nelson wayl...@wayland.id.au wrote:
On Sat, 4 Apr 2009, Xiao Yafeng wrote:
3. Could I define primary key for a bag variable?
All items in a Bag are primary keys, but there's no data additional
data associated with it.
I mean whether I can see Set as a table and Bag
On Fri, Apr 3, 2009 at 10:52 PM, Moritz Lenz mor...@faui2k3.org wrote:
Xiao Yafeng wrote:
1. Could I set multi-return type?like
sub test as (Int, Str) {...}
as is coercion - so to what would it coerce? Int or Str? How could the
compiler know? Or do you mean
1. Could I set multi-return type?like
sub test as (Int, Str) {...}
my (Int, Str) sub test {...}
or my (Int|Num, Str) sub test{...}
2. set is unordered collection of values， subset is new type. People are
apt to confuse
I've been thinking about that. One interesting ramification of
the current matching rule is that you could say either of:
foo.io ~~ :r :x
or
foo ~~ :io(:r :x)
where .io is whatever your casting method of choice is for turning
a string into an object with the correct methods.
Off the top of one's head, since there is no particular difference between
an operator and a function, can I see a function as a operator:
(1, 2, 3, 4) elems(2, 3, 4, 5) #(2, 2, 2, 2)
(1, 2, 3, 4) shift(2, 3, 4, 5) #(2, 3, 4, 5)
Moreover, can I see a subroutine as a operator:
On Sat, Aug 30, 2008 at 4:22 AM, Dave Whipp [EMAIL PROTECTED] wrote:
Lets say I want to find the 5th smallest element in an array. I might
write:
@array.sort.[4];
How does the implementation of the sort function know that I just want to
5th item (and thus choose an appropriate
There are no barewords in Perl 6, but it seems new method is an exception:
class Dog {
has $name;
method bark () {
say $name;
}
}
my $p = Dog.new($name = 'boo');
$p.bark;#error!
my $p = Dog.new( name = 'boo');
I've read Synopsis and I wondered why to treat max and min as
operator. IMHO, view them as list functions is more reasonable. Like
below:
@test.max
is clearer than
@test[0] max @test[1] or [max] @test.
Any reply would be really appreciated and will much help me learn
perl6. Thanks in
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