Re: EX3: Adverbs and print()

2001-10-10 Thread Bart Lateur
On Sat, 06 Oct 2001 22:20:49 -0400, John Siracusa wrote: So, in the … operator, the filter is the adverb: $sum = … @costs : {$^_ 1000}; WTF is that operator? All I see is a black block. We're not in ASCII any more, Toto... -- Bart.

Re: EX3: Adverbs and print()

2001-10-10 Thread Piers Cawley
Bart Lateur [EMAIL PROTECTED] writes: On Sat, 06 Oct 2001 22:20:49 -0400, John Siracusa wrote: So, in the … operator, the filter is the adverb: $sum = … @costs : {$^_ 1000}; WTF is that operator? All I see is a black block. We're not in ASCII any more, Toto... I'm guessing

Re: EX3: Adverbs and print()

2001-10-10 Thread John Siracusa
On 10/10/01 7:27 AM, Piers Cawley wrote: Bart Lateur [EMAIL PROTECTED] writes: On Sat, 06 Oct 2001 22:20:49 -0400, John Siracusa wrote: So, in the … operator, the filter is the adverb: $sum = … @costs : {$^_ 1000}; WTF is that operator? All I see is a black block. We're not in

RE: EX3: Adverbs and print()

2001-10-07 Thread Brent Dax
Damian Conway: # So, in the … operator, the filter is the adverb: # # $sum = … @costs : {$^_ 1000}; # # Does that mean that in the built-in print, the file # handle is the only # in-band argument, and all the actual items to be # printed are merely # adverbs? # #

EX3: Adverbs and print()

2001-10-06 Thread John Siracusa
From EX3: A subroutine's adverbs are specified as part of its normal parameter list, but separated from its regular parameters by a colon: my sub operator:… is prec(\operator:+($)) ( *@list : $filter //= undef) { ... This specifies that operator:… can take a single scalar adverb, which is