Miércoles 14 Abril 2004 14:18, Juerd wrote:
> I propose to use ` as a simple hash subscriptor, as an alternative
> to {} and <<>>. It would only be useable for \w+ keys or perhaps
> -?\w+. As with methods, a simple "atomic" (term exists only in
> perlreftut, afaix, but I don't know another word to
Angel Faus skribis 2004-04-19 22:43 (+0200):
> If we really need a ultra-huffman encoding for hash subscriptors, I
> have always dreamt of being able to do:
> %hash/key
> $hashref/foo/bar/baz/quux
> ...
I'd hate to give up dividing slash. It's one of the few operators that I
sometimes type
[EMAIL PROTECTED] (Juerd) writes:
> Angel Faus skribis 2004-04-19 22:43 (+0200):
>> If we really need a ultra-huffman encoding for hash subscriptors, I
>> have always dreamt of being able to do:
>> %hash/key
>> $hashref/foo/bar/baz/quux
>> ...
>
> I'd hate to give up dividing slash. It's on
Sean O'Rourke skribis 2004-04-19 15:11 (-0700):
> > I'd hate to give up dividing slash. It's one of the few operators that I
> > sometimes type without whitespace. Simple because 1/10 is good enough
> > and 1 / 10 is very wide.
> You can have both, though.
But not in a way that makes $foo/$bar div
[EMAIL PROTECTED] (Juerd) writes:
> Sean O'Rourke skribis 2004-04-19 15:11 (-0700):
>> > I'd hate to give up dividing slash. It's one of the few operators that I
>> > sometimes type without whitespace. Simple because 1/10 is good enough
>> > and 1 / 10 is very wide.
>> You can have both, though.
>
On Mon, Apr 19, 2004 at 03:34:13PM -0700, Sean O'Rourke wrote:
in a '/' is a regex, anything otherwise is a hash slice.
I don't understand. Could you give some examples? Is this in the context
of bare /path/to/foo, even?
/foo/ # trailing slash -- so it's a regexp (m/foo/)
/foo\/bar/ #
Sean O'Rourke skribis 2004-04-19 15:34 (-0700):
> I'm saying "division" is now defined such that when the numerator is
> a hash(-ref), the result is the set of values associated with the
> denominator. I've never tried to divide a hash or hashref by
> something without it being a bug.
I understan
Sean O'Rourke wrote:
> I'm saying "division" is now defined such that when the numerator is
> a hash(-ref), the result is the set of values associated with the
> denominator. I've never tried to divide a hash or hashref by
> something without it being a bug.
Right...in Perl 5.
In Perl 6, a hash
