A 11 de fevereiro de 2020 10:47:34 CET, David Santiago
escreveu:
>A 11 de fevereiro de 2020 09:46:06 CET, David Santiago
>escreveu:
>>
>>Hi!
>>
>>Can someone explain me why this doesn't work:
>>
>>my Blob $read;
>>$read ~= $socket.read(1024);
>>
>>Dies with error:
>>
>>X::Buf::AsStr: Cannot use
You are using ~, which stringifies. Bufs are not strings: you need to
decode them to concatenate it to a string. If what you want is to
concatenate the buffer, probably ,= will work (not sure about this, would
have to check), or any other operator that works on Positionals.
JJ
El mar., 11 feb. 20
~ works fine for concatenating Bufs; For example:
my $a = Buf.new(1,2,3);
my $b = $a ~ Buf.new(4,5,6)
will assign correctly to $b.
I can't work out what the problem is here, despite trying various
combinations. Perhaps socket isn't really returning a Blob?
Kevin.
On Tue, 11 Feb 2020 at 21:01,
I think the problem is IO::Socket.read() returns a Blob not a Buf.
~ has a Buf, Buf variant : https://docs.raku.org/language/operators#infix_~
But not a Blob one. Buf does Blob but not vice versa.
I think you need to transform the output from .read into a Buf if you want
to use the ~= how you wa
Ok I 100% don't know after trying this out :
my Buf $a = Buf.new(1,2,3);
my Blob $b = Blob.new(4,5,6);
$a ~= $b;
say $a
And it worked fine so... I dunno.
On Tue, 11 Feb 2020 at 11:00, Simon Proctor wrote:
> I think the problem is IO::Socket.read() returns a Blob not a Buf.
>
> ~ has a Buf, Bu
A 11 de fevereiro de 2020 12:03:19 CET, Simon Proctor
escreveu:
>Ok I 100% don't know after trying this out :
>
>my Buf $a = Buf.new(1,2,3);
>my Blob $b = Blob.new(4,5,6);
>$a ~= $b;
>say $a
>
>And it worked fine so... I dunno.
>
>
>On Tue, 11 Feb 2020 at 11:00, Simon Proctor wrote:
>
>> I think
On 11/02/2020 10:56, David Santiago wrote:
> Hi!
>
> Can someone explain me why this doesn't work:
>
> my Blob $read;
> $read ~= $socket.read(1024);
>
> Dies with error:
>
> X::Buf::AsStr: Cannot use a Buf as a string, but you called the Stringy
> method on it
>
> This also doesn't work:
>
> my Bu
Awesome explanation! Thank you!
BTW,
> my Blob $read = Buf.new;
Is it creating either a Blob or a Buf?
Regards,
David Santiago
--
Sent from my Android device with K-9 Mail. Please excuse my brevity.
On 11/02/2020 14:14, David Santiago wrote:
> Awesome explanation! Thank you!
>
> BTW,
>> my Blob $read = Buf.new;
> Is it creating either a Blob or a Buf?
>
> Regards,
> David Santiago
Hi David,
"my Blob $read" will define the variable $read to 1) only accept things
that typecheck against Blob,
The problem is that you are using ~ with an uninitialized Buf/Blob
my Buf $read;
$read ~ Buf.new;
# Use of uninitialized value element of type Buf in string context.
Note that it is not complaining about it being a Buf. It is complaining
about it being uninitialized.
If you initializ
Hi Timo,
Thanks for the answer:
> the liskov substitution principle
I didn't knew about this principle. I'm now going down the rabbit hole.
Is this always the case for all the derived classes in Raku?
Best regards,
David Santiago
Timo Paulssen escreveu no dia terça, 11/02/2020 à(s) 13:32:
>
>
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