100% thanks a lot. :)
On Tue, 9 Oct 2018 at 16:31, Timo Paulssen wrote:
> --output is for the compiler's compilation stages
>
> for example:
>
> timo@schmand ~> perl6 --output=/tmp/outputtest --target=mbc -e 'say "hi"'
> timo@schmand ~> moar --dump /tmp/outputtest | head
>
> MoarVM dump of
--output is for the compiler's compilation stages
for example:
> timo@schmand ~> perl6 --output=/tmp/outputtest --target=mbc -e 'say "hi"'
> timo@schmand ~> moar --dump /tmp/outputtest | head
>
> MoarVM dump of binary compilation unit:
>
> SC_0 : B1DFAD9164F11E967B354508CC458ABAB8DEDC27
>
It feels like a bug. I more wanted to know if anyone knew anything about it
for the talk.
Thanks
On Tue, 9 Oct 2018, 14:49 Brad Gilbert, wrote:
> My guess is that this is a bug.
>
> You can work around it by adding
>
> my $*OUT = q[test].IO.open(:w);
>
> in front of the code.
> On Tue, Oct
So... I'm working through some notes for a talk on Thursday and I am trying
to work out how the --output flag is supposed to work.
I would expect this to create a file called test and print "Hi\n" in it :
perl6 --output=test -e 'say "Hi"'
But instead I got Hi printed to the command line and an