* Thom Brown (thombr...@gmail.com) wrote:
> psql -U postgres -d test -c "select tablename,
> pg_size_pretty(pg_table_size(tablename::regclass)) from pg_tables
> where schemaname = 'public' order by tablename;"
>
> And this, for some reason, works... which is how I did it the other
> day (hence why
On 27 May 2010 23:00, Tom Lane wrote:
> Thom Brown writes:
>> This probably isn't a legitimate bug, but as a precaution
>> I'm running the following command against PostgreSQL 9.0 beta 1:
>
>> psql -U postgres -d test -c "select tablename,
>> pg_size_pretty(pg_table_size(tablename::regclass))
Thom Brown writes:
> This probably isn't a legitimate bug, but as a precaution
> I'm running the following command against PostgreSQL 9.0 beta 1:
> psql -U postgres -d test -c "select tablename,
> pg_size_pretty(pg_table_size(tablename::regclass)) from pg_tables
> order by tablename;"
> And
On tor, 2010-05-27 at 22:41 +0100, Thom Brown wrote:
> This probably isn't a legitimate bug, but as a precaution
>
> I'm running the following command against PostgreSQL 9.0 beta 1:
>
> psql -U postgres -d test -c "select tablename,
> pg_size_pretty(pg_table_size(tablename::regclass)) from pg
This probably isn't a legitimate bug, but as a precaution
I'm running the following command against PostgreSQL 9.0 beta 1:
psql -U postgres -d test -c "select tablename,
pg_size_pretty(pg_table_size(tablename::regclass)) from pg_tables
order by tablename;"
And getting the following message:
