Can anyone tell me why this will not work?
select *,
CASE WHEN postcode ilike '%OO%' THEN ''
END
from addresses
where studentid=1234
and addresstype='C'
There are postcodes like this: OO00 0OO
Regards
Garry
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Garry Saddington [EMAIL PROTECTED] writes:
Can anyone tell me why this will not work?
select *,
CASE WHEN postcode ilike '%OO%' THEN ''
END
from addresses
...
Define not work. What are you expecting it to do versus what
really happens?
Right offhand it looks like the CASE will return
On Wednesday 24 September 2008 21:03, Tom Lane wrote:
Garry Saddington [EMAIL PROTECTED] writes:
Can anyone tell me why this will not work?
select *,
CASE WHEN postcode ilike '%OO%' THEN ''
END
from addresses
...
Define not work. What are you expecting it to do versus what
On Wed, Sep 24, 2008 at 3:22 PM, Garry Saddington
[EMAIL PROTECTED] wrote:
select *,
CASE WHEN postcode ilike '%OO%' THEN ''
END
from addresses
It does work but returns a column called case. How can I return the case
column as 'postcode'?
You have to give an Alias to this column name
On 24/09/2008 23:22, Garry Saddington wrote:
Garry Saddington [EMAIL PROTECTED] writes:
CASE WHEN postcode ilike '%OO%' THEN ''
END
from addresses
It does work but returns a column called case. How can I return the case
column as 'postcode'?
...case when postcode ilike '%OO%' then '' end
BTW, should you have an else clause in there? - What happens when the
comparison fails?
As Tom said, a null value would be returned.
Garry Saddington wrote:
It does work but returns a column called case. How can I return the case
column as 'postcode'?
select
CASE WHEN postcode ilike '%OO%' THEN ''
END as postcode
from addresses
--
Guy Rouillier
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