Great, thanks!
On Thu, Jun 19, 2008 at 5:14 PM, Sam Mason <[EMAIL PROTECTED]> wrote:
> On Thu, Jun 19, 2008 at 03:38:28PM -0400, blackwater dev wrote:
> > The problem is name is not one column but made up of firstname,
> > lastname...how do I do this?
>
> I'd probably do something like:
>
> SELE
On Thu, Jun 19, 2008 at 03:38:28PM -0400, blackwater dev wrote:
> The problem is name is not one column but made up of firstname,
> lastname...how do I do this?
I'd probably do something like:
SELECT firstname, lastname, COUNT(*)
FROM people
GROUP BY firstname, lastname
HAVING COUNT(*) >
-> -Original Message-
-> From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of blackwater dev
-> Sent: 19 juin 2008 15:38
-> To: pgsql-general@postgresql.org
-> Subject: [GENERAL] finding firstname + lastname groups
->
-> I have to find the same firstname+ lastna
On Thu, Jun 19, 2008 at 1:38 PM, blackwater dev <[EMAIL PROTECTED]> wrote:
> I have to find the same firstname+ lastname combo in my db and see which
> name appears the most so I basically need to do the following:
>
> select name, count(name) from people group by name having count(name)>1
>
> The
I have to find the same firstname+ lastname combo in my db and see which
name appears the most so I basically need to do the following:
select name, count(name) from people group by name having count(name)>1
The problem is name is not one column but made up of firstname,
lastname...how do I do th