On Sat, May 30, 2015 at 9:10 PM, Andreas Kretschmer
wrote:
> Michael Paquier wrote:
>
>>
>> Append the new value to it the existing field, jsonb has as property
>> to enforce key uniqueness, and uses the last value scanned for a given
>> key.
>
> can you show a simple example, how to append a jso
Glyn Astill wrote:
> Prior to 9.5 you can't, I think you have to use something like jsonb_each to
> unwrap it then wrap it back up again.
>
> The jsonbx extension, which I believe is what ended up in 9.5 has a simple
> concatenate function (here: https://github.com/erthalion/jsonbx), I also ha
- Original Message -
> From: Andreas Kretschmer
> To: pgsql-general@postgresql.org
> Cc:
> Sent: Saturday, 30 May 2015, 13:10
> Subject: Re: [GENERAL] replacing jsonb field value
>
> Michael Paquier wrote:
>
>>
>> Append the new value to
Michael Paquier wrote:
>
> Append the new value to it the existing field, jsonb has as property
> to enforce key uniqueness, and uses the last value scanned for a given
> key.
can you show a simple example, how to append a jsonb to an jsonb-field?
Maybe i'm blind, but i can't find how it works.
On Sat, May 30, 2015 at 11:52 AM, john.tiger wrote:
> using 9.4.2
>
> suppose we have
> create table test (id serial primary key, data jsonb);
> insert into test (data) values ({"a":1, "b":2})
>
> want to replace "b" with 3
>
> okay, we are retrieving entire record
> res = select * from test where
using 9.4.2
suppose we have
create table test (id serial primary key, data jsonb);
insert into test (data) values ({"a":1, "b":2})
want to replace "b" with 3
okay, we are retrieving entire record
res = select * from test where data ->> b = 2
newrec = res
newrec["b" = 3
delete from test where
