On Fri, Jun 23, 2017 at 2:58 AM, Alvaro Herrera
wrote:
> Ashutosh Bapat wrote:
>> On Mon, Jun 5, 2017 at 8:22 AM, atorikoshi
>> wrote:
>> > Hi,
>> >
>> > I found below formula to compute selectivities, but
>> > I think the last
On 2017/06/23 6:28, Alvaro Herrera wrote:
Ashutosh Bapat wrote:
On Mon, Jun 5, 2017 at 8:22 AM, atorikoshi
wrote:
Hi,
I found below formula to compute selectivities, but
I think the last Probability 'P(b=?)' should be 'P(c=?)'.
P(a=?,b=?,c=?) =
Ashutosh Bapat wrote:
> On Mon, Jun 5, 2017 at 8:22 AM, atorikoshi
> wrote:
> > Hi,
> >
> > I found below formula to compute selectivities, but
> > I think the last Probability 'P(b=?)' should be 'P(c=?)'.
> >
> >> P(a=?,b=?,c=?) = P(a=?,b=?) * (d +
On Mon, Jun 5, 2017 at 8:22 AM, atorikoshi
wrote:
> Hi,
>
> I found below formula to compute selectivities, but
> I think the last Probability 'P(b=?)' should be 'P(c=?)'.
>
>> P(a=?,b=?,c=?) = P(a=?,b=?) * (d + (1-d)*P(b=?))
>
>
> Attached patch fixes it, and
Hi,
I found below formula to compute selectivities, but
I think the last Probability 'P(b=?)' should be 'P(c=?)'.
P(a=?,b=?,c=?) = P(a=?,b=?) * (d + (1-d)*P(b=?))
Attached patch fixes it, and it also adds some spaces
following another formula which is on line 86 and
computes P(a=?, b=?).