Hi Cedar,
Does this help?
select CURRENT_TIMESTAMP, CURRENT_TIMESTAMP + '90 days';
timestamp|?column?
+
2001-04-24 12:57:56+01 | 2001-07-23 12:57:56+01
>
> I also have a question.. How, for example, would I add 90
Hi Boulat,
stasis=# select (now() + '1 year')::date;
?column?
2002-03-06
(1 row)
Hope this helps
Francis
> Hi,
>
> Im a little bit stuck here.
>
> Does anyone know how to get date in format '-MM-DD' of a date one
> year from now.
> So for example today is '2001-03-06' I
r money values? Is numeric(9,2) the best choice for
> money? I
I am using numeric(9,2) for all my "money" values with VB6 and it works
fine. I use a wrapper function that I wrote to "fix up" arguments so
that postgres plays nicely with them. I tend to manipulate recordset
values with VB/VBA's conversion functions after they're returned, like
CCur() as mentioned above. I'm willing to share my wrappers if you'd
like them.
Hope this helps
Francis Solomon
. You might try doing something like this:
For a certain month/year:
SELECT field FROM table WHERE date_part('year', datefield)=1999 AND
date_part('month', datefield)=9;
For a date range:
SELECT field FROM table WHERE datefield BETWEEN '1999-09-01' AND
&#x
Hi Boris,
I know Kaare Rasmussen posted a URL to the online documentation already,
but this might be a direct solution to your problem:
DELETE FROM onlineuser WHERE datum < ('now'::datetime - '5
minutes'::interval);
Hope this helps
Francis Solomon
> Hello
>
Hi Brian,
Try something like this:
SELECT firstname FROM table1 WHERE firstname NOT IN (SELECT firstname
FROM table2 WHERE table2.date='yesterday'::date);
Hope this helps.
Francis Solomon
>
> What do I have to do a query where information in table1 is
> not in table2
&
u'll get results like:
@2000-12-14 @
So, you could modify your query to do:
select foo from table where substr(datefoo, 1, 10) = '2000-12-14';
Alternatively, what's wrong with this approach?
select foo from table where date(datefoo) = '2000-12-14';
I think that might
Hi Daniel,
Try this as your query:
SELECT to_char(field, 'DD/MM/') AS "new name";
Hope this helps
Francis Solomon
>
> In MS Access is:
> SELECT FORMAT([field],'DD/MM/') AS new name;
> How I can make in pgaccess?
>
> Daniel
Hi Borek,
What version of PostgreSQL are you using? This works fine for me on
7.02. Time to update, maybe?
Hope this helps
Francis
>
>Hello all,
>
>My following problem is:
>
> swports=# select substring(cp from 1 for 4)::int4 from out2cp;
> ERROR: pg_atoi: error in "6.1,": can't pars
Hi,
The syntax you used works fine for me.
francis=# select version();
version
---
PostgreSQL 7.0.2 on i686-pc-linux-gnu, compiled by gcc 2.95.2
(1 row)
Hope this helps
Francis Solomon
> -Origi
tive regex match. If you really want a
'like' match, you could do this instead:
SELECT * FROM abbrev where long_name~~('%' || abbr || '%');
... where '||' is the string-concatenation operator.
Hope this helps
Francis Solomon
> -Original Message-
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