--- On Wed, 4/21/10, Thomas BOURIMECH wrote:
From: Thomas BOURIMECH
Subject: [SQL] LEFT OUTER JOIN issue
To: "'pgsql-sql@postgresql.org'"
Date: Wednesday, April 21, 2010, 9:06 AM
Hi everyone, here is my problem :
I got two tables :
CREATE TABLE
"public"."calendar_t
--- On Thu, 10/8/09, sub3 wrote:
From: sub3
Subject: [SQL] Pulling additional columns with aggregate
To: pgsql-sql@postgresql.org
Date: Thursday, October 8, 2009, 1:14 PM
Hi,
I have 2 tables. I want to be able to calculate the closest value in one
(tempvalues), to the closest value in the ot
-- On Thu, 3/12/09, Marco Lechner
wrote:
> From: Marco Lechner
> Subject: Re: [SQL] Permanent alias for postgresql table
> To: pgsql-sql@postgresql.org
> Date: Thursday, March 12, 2009, 2:26 PM
> Hi Mina,
>
> thanks for your answer. I thought about that, but don't
> views decrease performance
--- On Fri, 11/28/08, Lutz Steinborn <[EMAIL PROTECTED]> wrote:
> From: Lutz Steinborn <[EMAIL PROTECTED]>
> Subject: [SQL] wired behaviour
> To: pgsql-sql@postgresql.org
> Date: Friday, November 28, 2008, 1:51 PM
> Hello,
>
> I have an problem understanding a simple query:
>
> For example I
--- On Fri, 9/26/08, Edward W. Rouse <[EMAIL PROTECTED]> wrote:
> From: Edward W. Rouse <[EMAIL PROTECTED]>
> Subject: Re: [SQL] Problem with pg_connect() in PHP
> To: "'pgsql-sql'"
> Date: Friday, September 26, 2008, 5:23 PM
> Can I assume the missing ‘.”’ From the end of
> PG_PASSWORD is a c
--- On Mon, 9/8/08, Ruben Gouveia <[EMAIL PROTECTED]> wrote:
> From: Ruben Gouveia <[EMAIL PROTECTED]>
> Subject: [SQL] PL/pgSQL function syntax question?
> To: "pgsql-sql"
> Date: Monday, September 8, 2008, 9:40 PM
> i get the following error when i try and create the
> following function:
>
--- On Thu, 9/4/08, Ruben Gouveia <[EMAIL PROTECTED]> wrote:
> From: Ruben Gouveia <[EMAIL PROTECTED]>
> Subject: [SQL] Correct Insert SQL syntax?
> To: "pgsql-sql"
> Date: Thursday, September 4, 2008, 10:16 PM
> Will this syntax work:
>
> fcn_stats are all in the same schema
>
> CREATE OR R
> Hi all,
>
> I was wondering if there is a way to concatenate the
> results of a field in a
> select to return it as a single string.
>
> Example :
>
> my_field
> --
> 1
> 2
> 3
>
> select concat_something(my_field) from my_table group by
> something;
> the result expected would be
--- On Tue, 8/19/08, Edward W. Rouse <[EMAIL PROTECTED]> wrote:
> From: Edward W. Rouse <[EMAIL PROTECTED]>
> Subject: Re: [SQL] Join question
> To: "'Daniel Hernandez'" <[EMAIL PROTECTED]>, pgsql-sql@postgresql.org
> Date: Tuesday, August 19, 2008, 1:35 PM
> I have tried left, right outer and
use md5 function in a trigger when insert data
or see this link
http://www.postgresql.org/docs/8.3/static/pgcrypto.html
--- On Mon, 7/28/08, Chris Preston <[EMAIL PROTECTED]> wrote:
> From: Chris Preston <[EMAIL PROTECTED]>
> Subject: [SQL] Encrytion in postgres field in table
> To: pgsql-sql@
The truncate is more fast to delete, the truncate command not scan the table
http://www.postgresql.org/docs/8.3/static/sql-truncate.html
--- On Thu, 7/24/08, A. Kretschmer <[EMAIL PROTECTED]> wrote:
> From: A. Kretschmer <[EMAIL PROTECTED]>
> Subject: Re: [SQL] truncate vs. delete
> To: pgsql-s
i think this work
select id,count from table group by to_char(date,'MM')
--- On Wed, 7/16/08, A. Kretschmer <[EMAIL PROTECTED]> wrote:
> From: A. Kretschmer <[EMAIL PROTECTED]>
> Subject: Re: [SQL] How to GROUP results BY month
> To: pgsql-sql@postgresql.org
> Date: Wednesday, July 16, 2008, 5:
--- On Thu, 7/10/08, aldy <[EMAIL PROTECTED]> wrote:
> From: aldy <[EMAIL PROTECTED]>
> Subject: Re: [SQL] i can't connect after some periode
> To: pgsql-sql@postgresql.org
> Date: Thursday, July 10, 2008, 8:16 AM
> From: "A. Kretschmer"
> <[EMAIL PROTECTED]>
> Sent: Thursday, July 10, 2008 14:
what is the message error?
i have a similar problem whit a software, this software not closed the
connection to the server and not reuse the previously open.
--- On Thu, 7/10/08, aldy <[EMAIL PROTECTED]> wrote:
> From: aldy <[EMAIL PROTECTED]>
> Subject: [SQL] i can't connect after some peri
select * from (
SELECT DISTINCT a, b, c, now(), count(item_pk)
FROM product
LEFT JOIN item ON item.product_fk = product_pk
WHERE ...
GROUP BY a, b, c
) t1 where not exists (select a,b,c, from navigation t2 where t2.a = t1.a and
t2.b = t1.b and t2.c = t1.c)
--- On Thu, 6/26/08, Tarlika Elisabeth
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