Hi.
Can anyone explain me this behavior?
testdb=# select E'\\' = E'\\';
?column?
--
t
(1 row)
testdb=# select E'\\' like E'\\';
?column?
--
f
(1 row)
Shouldnt the like operator do the same as the = if there occours no
wildcards and stuff in the string?
--
Jesper
--
Sen
Jesper Krogh writes:
> Shouldnt the like operator do the same as the = if there occours no
> wildcards and stuff in the string?
If there are also no escape characters, then yeah.
FWIW, 8.4 will complain about this case:
regression=# select E'\\' like E'\\';
ERROR: LIKE pattern must not end wi
Tom Lane wrote:
Jesper Krogh writes:
Shouldnt the like operator do the same as the = if there occours no
wildcards and stuff in the string?
If there are also no escape characters, then yeah.
FWIW, 8.4 will complain about this case:
regression=# select E'\\' like E'\\';
ERROR: LIKE pattern
Jesper Krogh wrote:
Tom Lane wrote:
Jesper Krogh writes:
Shouldnt the like operator do the same as the = if there occours no
wildcards and stuff in the string?
If there are also no escape characters, then yeah.
FWIW, 8.4 will complain about this case:
regression=# select E'\\' like E'\\';
Jesper Krogh writes:
> Ok. The pattern has to be "double escaped"..
Or specify a different escape character.
regards, tom lane
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Jesper Krogh wrote:
So I cannot rely on the like operator to behave correct if I'd like to
compare strings with backslashes (e.g. filepaths from MS Windows
filesystems)?
test=# SELECT E'\\' LIKE E'\\' ESCAPE '';
?column?
--
t
(1 row)
--
Craig Ringer
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