On 7/25/06, Otniel Michael <[EMAIL PROTECTED]> wrote:
Mr. Aaron. I am sorry, your solution didn't match in my case. Example for your solution :A = 1B = 1C = 1D = 1E = 1F = 1G = 4G have 4 candy. Its too much for G.In my case, the solution is :
A = 1B = 1C = 1D = 1E = 2F = 2G = 2The extra candy is gi
Otniel Michael wrote:
Mr. Aaron. I am sorry, your solution didn't match in my case.
Example for your solution :
A = 1
B = 1
C = 1
D = 1
E = 1
F = 1
G = 4
G have 4 candy. Its too much for G.
In my case, the solution is :
A = 1
B = 1
C = 1
D = 1
E = 2
F = 2
G = 2
The extra candy is given to thr
Mr. Aaron. I am sorry, your solution didn't match in my case. Example for your solution :A = 1B = 1C = 1D = 1E = 1F = 1G = 4G have 4 candy. Its too much for G.In my case, the solution is :A = 1B = 1C = 1D = 1E = 2F = 2G = 2The extra candy is given to three child.Do you have the other solution? I ne
On 7/25/06, Otniel Michael <[EMAIL PROTECTED]> wrote:
Dear All,I have a problem with this case :I have 10 candy for 7 child (A, B, C, D, E, F, G).Table X :code value --- A 0 B 0 C 0
D 0 E 0 F 0
Dear All,I have a problem with this case :I have 10 candy for 7 child (A, B, C, D, E, F, G).Table X :code value --- A 0 B 0 C 0 D 0 E 0 F 0 G 0 And I want divide it with this algo
