On May 11, 2006, at 21:00 , Christian Paul Cosinas wrote:
For example I have a table like this
ID Name
1 A
1 B
2 C
2 D
And I have a Query like this:
SELECT * FROM table ORDER BY ID.
Would my result always give me the same order or is there may be a
possible
di
Hi,
For example I have a table like this
ID Name
1 A
1 B
2 C
2 D
And I have a Query like this:
SELECT * FROM table ORDER BY ID.
Would my result always give me the same order or is there may be a possible
different result?
For example?
1 B
1 A
2 D
Gary Stainburn <[EMAIL PROTECTED]> writes:
> > Alternatively: (a<>6),(a<>4),a
>
> Although this does exactly what I want, at first glance it should do
> exactly the opposite.
>
> I'm guessing that for each line it evaluates
> not (a=6) 0 for true else 1
Not really, "not a=6" is an expression t
On Wed, Mar 09, 2005 at 12:41:55 +,
Gary Stainburn <[EMAIL PROTECTED]> wrote:
> Hi folks.
>
> I seem to remember somewhere being shown how to bump specific rows to
> the top of a list; something along the lines of:
>
> select c_id as key, c_des as value from customers order by c_id = 7,
>
On Wednesday 09 March 2005 1:06 pm, you wrote:
> Gary Stainburn wrote:
> > Hi folks.
> >
> > I seem to remember somewhere being shown how to bump specific rows
> > to the top of a list; something along the lines of:
> >
> > select c_id as key, c_des as value from customers order by c_id =
> > 7, c_
O Gary Stainburn έγραψε στις Mar 9, 2005 :
> Hi folks.
>
> I seem to remember somewhere being shown how to bump specific rows to
> the top of a list; something along the lines of:
>
> select c_id as key, c_des as value from customers order by c_id = 7,
> c_id = 160, value;
use the
case ... w
Gary Stainburn wrote:
Hi folks.
I seem to remember somewhere being shown how to bump specific rows to
the top of a list; something along the lines of:
select c_id as key, c_des as value from customers order by c_id = 7,
c_id = 160, value;
Looks roughly right.
SELECT * FROM foo ORDER BY not(a=6),
Hi folks.
I seem to remember somewhere being shown how to bump specific rows to
the top of a list; something along the lines of:
select c_id as key, c_des as value from customers order by c_id = 7,
c_id = 160, value;
however, although the statement is accepted the two rows specified are
not b
> This seems like the answer must be pretty easy, but I can't think of it:
>
> In the following statement:
>
> select field1 from my_table where field2 in (3, 1, 2);
>
> How can I modify this statement so that the record are returned in the
> order of first those records having field2 = 3, then f
This seems like the answer must be pretty easy, but I can't think of it:
In the following statement:
select field1 from my_table where field2 in (3, 1, 2);
How can I modify this statement so that the record are returned in the
order of first those records having field2 = 3, then field2 = 1, the
This seems like the answer must be pretty easy, but I can't think of it:
In the following statement:
select field1 from my_table where field2 in (3, 1, 2);
How can I modify this statement so that the record are returned in the
order of having field2 = 3, then field2 = 1, then field2 = 2.
As it
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