Thanks to Josh, Richard, Tom
EXECUTE ''SELECT CAST(''
|| quote_ident($1)
|| '' AS TEXT) AS foo FROM ''
|| quote_ident($2)
and then
list := list || '', '' || this_record.foo ;
works perfectly.
Regards, Christoph
---(end of broadcast)--
Chris,
> FOR this_record IN
> EXECUTE ''SELECT ''
> || quote_ident($1)
> || ''FROM ''
> || quote_ident($2)
> LOOP
> list := list || '', '' || this_record.$1 ;
> END LOOP;
>
> As expected, accessing a field via this_record.$1
> does not work.
> Can it be done otherwise?
Christoph Haller <[EMAIL PROTECTED]> writes:
> Consider the following PLpgSQL code fragment
> FOR this_record IN
> EXECUTE ''SELECT ''
> || quote_ident($1)
> || ''FROM ''
> || quote_ident($2)
> LOOP
> list := list || '', '' || this_record.$1 ;
> END LOOP;
> As expected,
On Thursday 07 Nov 2002 2:35 pm, Christoph Haller wrote:
> Consider the following PLpgSQL code fragment
>
> FOR this_record IN
> EXECUTE ''SELECT ''
>
> || quote_ident($1)
> || ''FROM ''
> || quote_ident($2)
>
> LOOP
> list := list || '', '' || this_record.$1 ;
> END LOO
Consider the following PLpgSQL code fragment
FOR this_record IN
EXECUTE ''SELECT ''
|| quote_ident($1)
|| ''FROM ''
|| quote_ident($2)
LOOP
list := list || '', '' || this_record.$1 ;
END LOOP;
As expected, accessing a field via this_record.$1
does not work.
Can it be d
