2007/7/27, Carol Cheung <[EMAIL PROTECTED]>:
db=# select * from tester order by birth_year;
birth_year | salary
+
1946 | 78000
1949 | 61000
What is the data type of the birth_year column? I'd suggest using
date if you can, as what it is is a date with
On 7/27/07, I wrote:
> On 7/27/07, Carol Cheung <[EMAIL PROTECTED]> wrote:
> > Something like:
> >
> > decade | average(salary)
> > ---+-
> >1940 | 69500
> >1950 | 5.33
> >1960 | 53000
> >1970 | 40333.33
>
> CREATE TABLE tester (
> birth_year integer,
>
Hello
you can use CASE like
SELECT CASE
WHEN birth_year BETWEEN 1940 AND 1949 THEN 1940
WHEN birth_year BETWEEN 1950 AND 1959 THEN 1950
WHEN birth_year BETWEEN 1960 AND 1969 THEN 1960
WHEN birth_year BETWEEN 1970 AND 1979 THEN 1979 END, AVG(salary)
FROM tester GROUP BY 1 ORDER BY 1;
R
On 7/27/07, Carol Cheung <[EMAIL PROTECTED]> wrote:
> Something like:
>
> decade | average(salary)
> ---+-
>1940 | 69500
>1950 | 5.33
>1960 | 53000
>1970 | 40333.33
CREATE TABLE tester (
birth_year integer,
salary numeric(10,2)
);
SELECT
SUBSTRING(T
Carol Cheung wrote:
Hello,
Here's my table:
db=# select * from tester order by birth_year;
birth_year | salary
+
1946 | 78000
1949 | 61000
1951 | 58000
1953 | 56000
1958 | 52000
1962 | 5
1965 | 45000
1967 |
Hello,
Here's my table:
db=# select * from tester order by birth_year;
birth_year | salary
+
1946 | 78000
1949 | 61000
1951 | 58000
1953 | 56000
1958 | 52000
1962 | 5
1965 | 45000
1967 | 6
1968 |
