Re: [SQL] sum timestamp result in hours

2008-11-07 Thread Scott Marlowe
On Fri, Nov 7, 2008 at 9:36 AM, paulo matadr <[EMAIL PROTECTED]> wrote: > I change form to create query but basically need > sum(rgat.rgat_tmencerramento - rgat.rgat_tmregistroatendimento) = result in > hours > sumary: > rgat.rgat_tmencerrament = timestamp column > gat.rgat_tmregistroatendimento =

Res: [SQL] sum timestamp result in hours

2008-11-07 Thread paulo matadr
<[EMAIL PROTECTED]> Para: paulo matadr <[EMAIL PROTECTED]> Enviadas: Sexta-feira, 7 de Novembro de 2008 12:50:14 Assunto: Re: [SQL] sum timestamp result in hours 2008/11/7, paulo matadr <[EMAIL PROTECTED]>: > Select sum(age(rgat.rgat_tmencerramento, rgat.rgat_tmregistr

[SQL] sum timestamp result in hours

2008-11-07 Thread paulo matadr
Select sum(age(rgat.rgat_tmencerramento, rgat.rgat_tmregistroatendimento)) from atendimentopublico.registro_atendimento rgat inner join cadastro.localidade loca on loca.loca_id=rgat.loca_id inner join atendimentopublico.solicitacao_tipo_especificacao step on step.step_id=rgat.step_id where date(rg