Hi PFC
Thanks for this! It has sped up complete - now in fact there is no delay!
A few tweaks had to be made to the code ; here it is:
select breakdown.alignment, sum(cnt) as num FROM
( (select alignment.name as class, count(1) as cnt
from weapons,
alignment
where weapons
If I understand well a person has all the free weapons which have a level
<= to his own level, and of course all the weapons he bought.
1) get da weapons
One query can only use one index. Bad for you !
Let's split the free and non-free weapons.
1a) free weapons
S
