Re: [SQL] Aggregate question (Sum)

2007-11-19 Thread Luiz K. Matsumura
Hi Rodrigo, thanks for reply Rodrigo De León wrote: On Nov 19, 2007 3:46 PM, Luiz K. Matsumura <[EMAIL PROTECTED]> wrote: If someone can give me some hint I will apreciate. This is more of a normalization problem. See: http://www.deeptraining.com/litwin/dbdesign/FundamentalsOfRelatio

Re: [SQL] Aggregate question (Sum)

2007-11-19 Thread Rodrigo De León
On Nov 19, 2007 3:46 PM, Luiz K. Matsumura <[EMAIL PROTECTED]> wrote: > If someone can give me some hint I will apreciate. This is more of a normalization problem. See: http://www.deeptraining.com/litwin/dbdesign/FundamentalsOfRelationalDatabaseDesign.aspx and lookup Third Normal Form. You have

Re: [SQL] aggregate question

2003-06-24 Thread Tomasz Myrta
Dnia 2003-06-24 00:04, Użytkownik Tomasz Myrta napisał: select package_name, count(*) as n_packages from packages join package_log using (package_id); And one more: select package_name, sum(case when package_log.package_id is not null then 1 else 0 end) as n_packages from packages left

Re: [SQL] aggregate question

2003-06-24 Thread Hubert Lubaczewski
On Mon, 23 Jun 2003 13:59:52 -0500 (CDT) "Ryan" <[EMAIL PROTECTED]> wrote: > package_id | integer | not null default > I must be a total space case today because I can't hammer out the sql to > get a listing of all the packages with a count() of the package_log by > package_id. if you would

Re: [SQL] aggregate question

2003-06-23 Thread Tomasz Myrta
Dnia 2003-06-23 20:59, Użytkownik Ryan napisał: I know this one is simple enough. I have two tables: packages and package_log. I must be a total space case today because I can't hammer out the sql to get a listing of all the packages with a count() of the package_log by package_id. Thanks, Ryan