On Thursday 04 March 2004 11:20, Philippe Lang wrote:
[working query]
> It works fine.
Excellent! :-)
Oh - there's more :-(
> Now, I need to do something else: the parameter of my sub-select is also
> a member of the table I'm selecting.
>
> SELECT
>
> tableA.field1,
> tableA.field2,
>
> t
>
> Hello,
>
> Imagine the following query:
>
> ---
> SELECT
>
> tableA.field1,
> tableA.field2,
> =20=20
> tableB.field1,
> tableB.field2,
>
> (
> SELECT tableC.field2
> FROM tableC
> WHERE tableC.field1 =3D tableB.field1 - 1;
>
