e SQL statement as a
string used through the Statement class, so I tried using a
PreparedStatement, but I am still getting the same problem.
--
Jayson Callaway
---(end of broadcast)---
TIP 5: Have you checked our extensive FAQ?
http://www.postgresq
error that says it can not create the reference
because the table category does not exist.
How do I setup this type of reference structure in 7.1.2? Did the syntax
change?
I am running under Linux.
--
Jayson Callaway
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TIP 1
,
"parent_category_uid" int4 NULL REFERENCES test_cat(uid)
);
psql:test:6: NOTICE: CREATE TABLE/PRIMARY KEY will create implicit index
'test_cat_pkey' for table 'test_cat'
psql:test:6: NOTICE: CREATE TABLE will create implicit trigger(s) for
FOREIGN KEY chec
