Because to calculate the result, the block must always be evaluated, so it's a
bit redundant.
--
Cheers,
Peter.
On 2 feb 2012, at 17:08, Robert Sirois wrote:
> Ok, this may be from a simple lack of understanding, but I just have to know
> ;)
>
> Why can I call #or: (Boolean and friends) wit
Ok, this may be from a simple lack of understanding, but I just have to know ;)
Why can I call #or: (Boolean and friends) with a block, but #xor: only takes a
Boolean? I would think the paradigm would remain the same and be able to
compose operators like #or:, etc.?
What am I missing? Thanks!
RS
